Wavelength, period of vibration in seconds

AI Thread Summary
The discussion focuses on converting wavenumber to wavelength to find the period of vibration. The user initially confuses wavenumber with wavelength, leading to incorrect unit calculations. Correct formulas include T = 1/f and f = c/lambda, where lambda should be in meters. It is clarified that the wavenumber has units of inverse meters, not meters, and the correct approach is to convert wavenumber to wavelength before calculating the period. The user resolves their confusion and thanks the contributors for their help.
Rick2015
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< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >[/color]

Okay, I am having trouble with the units. I have the values for the wavenumber and I am trying to find the period.
These are the formulas that I am trying.
T = 1/f ; f = c/lambda

example: lambda = 3657 cm^-1 ; c = 2.998 x 10^8 m/s
I am doing 2.998 x 10^8 m/s / (3657 cm^1 x (1 cm/0.01m))
however, the unit for frequency is Hz = 1/s
I am getting m^2 on the denominator.
Am I using the right formulas?
thanks!
 
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Rick2015 said:
< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >

Okay, I am having trouble with the units. I have the values for the wavenumber and I am trying to find the period.
These are the formulas that I am trying.
T = 1/f ; f = c/lambda

example: lambda = 3657 cm^-1 ; c = 2.998 x 10^8 m/s
I am doing 2.998 x 10^8 m/s / (3657 cm^1 x (1 cm/0.01m))
however, the unit for frequency is Hz = 1/s
I am getting m^2 on the denominator.
Am I using the right formulas?
thanks!

By wavenumber, do you mean wavelength? If so, wavelength has units of meters, not 1/meters.
 
yes. it is the wavelength. But I am getting m^2
 
Rick2015 said:
yes. it is the wavelength. But I am getting m^2

So you are given the wavelength, and want to find the period? Start off with the conversion equation that makes sense in terms of units...

Period <s> = \frac{Wavelength [m]}{Velocity [\frac{m}{s}]}</s>
 
A wavelength has units of meters, not inverse meters.
Inverse meters suggest it is a wavenumber (usually called "k"). You can convert it to a wavelength, or directly use formulas with the wavenumber.
 
berkeman said:
So you are given the wavelength, and want to find the period? Start off with the conversion equation that makes sense in terms of units...

Period <s> = \frac{Wavelength [m]}{Velocity [\frac{m}{s}]}</s>

Not sure why my Latex isn't rendering correctly. It previews fine. Oh well, the old fashioned way:

Period [in seconds] = Wavelength [in meters] / Velocity [in meters/second]

EDIT -- I see now that using [ s ] without the spaces caused a strikethrough... Duh.
 
I got it! Thank you!
 
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