Weight and Gravity Relationship in Standing Objects

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The discussion revolves around the relationship between weight and gravity for a 100-meter pipe weighing 100 kg when positioned vertically versus horizontally. Participants clarify that gravity's strength near Earth's surface is uniform over short distances, meaning the pipe's weight remains effectively unchanged regardless of its orientation. However, a slight decrease in gravitational force can occur over much longer distances, such as 100,000 meters, resulting in approximately a 3% drop in weight. The original poster seeks to develop a formula to calculate the weight of various materials based on their density and tensile strength, inspired by an article from New Scientist. The conversation also touches on related concepts like the "skyhook" problem and space elevators.
Dave Chippy
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As part of a greater problem, i wonder if anyone could help me with this one. If i had a 100 meter length of pipe laid on the ground that wieghed say 100kg. if i stood the pipe up would the pipe wiegh less, allowing that the force of gravity decreases with the square of the distance from the Earth if so how would i calculate the new wieght. I hope someone can help thx.
 
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Unless the purpose of the exercise is to test your ability to integrate, for all practical purposes the strength of gravity near the Earth's surface can be considered uniform over 100 meters. The weight will be the same regardless of orientation.

What's the exact problem you are trying to solve?
 
the exact problem is a lot more complex and i know some one out there would maybe solve it easly, but if i can i would like to solve it myself with a little help. i used the length 100m and weight 100kg as arbitrary units easy to deal with. You say "for all practical purposes the strength of gravity near the Earth's surface can be considered uniform over 100 meters." What if my pipe were 100000mtrs?
 
There would be about a 3% drop in field strength over that distance. The strength of the field is inversely proportional to the square of the distance from the Earth's center.

If you state the exact problem, then it might become clear what's important and what's not.
 
thankyou Doc Al the exact problem goes like this. I was reading the New Scientist this morning and found this article http://www.newscientistspace.com/article/mg19125671.900;jsessionid=GBBIBOODMNDI
If you can't get the full article let me know and i;ll post it.
Any way here goes, if i knew what the length of cable was, its density and the gravitational decrease i would know its "weight". Now here is the problem i have created. If i could find the "weight" of a few different materials along with their tensile strengths etc i could maybe come up with a formulae to find the exact characteristics that would meet the requirments of the cable(maybe).
 
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Doc Al said:
Unless the purpose of the exercise is to test your ability to integrate, for all practical purposes the strength of gravity near the Earth's surface can be considered uniform over 100 meters. The weight will be the same regardless of orientation

You have a 100m long solid (not hollow) pipe and when you put it on the Earth's surface horizontally it weighs 100kg. Technically, if you put the same pipe vertically on the Earth's surface, its weight should go down (by an extremely small amount), right?
 
Swapnil said:
You have a 100m long solid (not hollow) pipe and when you put it on the Earth's surface horizontally it weighs 100kg. Technically, if you put the same pipe vertically on the Earth's surface, its weight should go down (by an extremely small amount), right?
Of course.
 
Dave Chippy said:
thankyou Doc Al the exact problem goes like this. I was reading the New Scientist this morning and found this article...
I could only see the beginning of the article, but it sounds a lot like the "skyhook" problem, which has been discussed a bit here on PF (and plenty of other places too). Do a search on "skyhook" (or "sky hook") as well as on "space elevator" and you might find some interesting stuff.

Here's one thread I found: https://www.physicsforums.com/showthread.php?t=74592
 
thx Al i'll be back
 
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