Weight of impact is from an object of 40kg that falls 50cm

  • Thread starter Thread starter Jeanette
  • Start date Start date
  • Tags Tags
    Impact Weight
AI Thread Summary
To calculate the impact force of a 40kg object falling 50cm, it's essential to understand that the force varies based on the materials involved and the object's geometry. The impact energy can be estimated using the formula e=mgh, where g is the acceleration due to gravity. The velocity at impact can be determined to be approximately 3.13 m/s. The deceleration during impact, which can reach hundreds of g's, is crucial for calculating the force using f=ma. Overall, the specifics of the impact scenario greatly influence the final force experienced.
Jeanette
Messages
1
Reaction score
0
Hi,

I have a basic question that i would be very thankful if someone could help me answer.

I need to find out what the weight of impact is from an object of 40kg that falls 50cm.

Many thanks.

Jeanette
 
Physics news on Phys.org
Welcom to PF.

The force an object imparts at impact is extremely difficult to determine with math alone (and isn't constant throughout the impact anyway). It depends on the material properties and geometry of the object being dropped and the object being hit.

The best you can do with ease is impact energy, which for a dropped object far below terminal velocity is just e=mgh

If you know the deceleration, though, you can use f=ma. If you drop a hard object on a hard floor, the deceleration can be hundreds of g's.
 
I would first find the velocity at the moment of impact

D = 1/2*a*t^2
.5 = 1/2*9.8*t^2

t=.319

Vf = Vo + a*t^2
Vf = 0 + 9.8*.319 = 3.13 m/s

The time it takes to lose velocity (or acceleration) can depend upon what surface it's hitting, way it lands etc. as mentioned in the above post. But the force of impact will be the mass times the acceleration (velocity divided by time it takes to go from 3.13 m/s to 0 m/s). Hope this helped, and I also hope I didn't make a mistake on silly kinematics equations.
 
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top