What affects tangential acceleration and normal or c?

AI Thread Summary
Acceleration can be greater than zero even when velocity is zero due to the presence of a net force acting on an object, indicating that acceleration depends on the resultant force. Tangential acceleration affects the speed of an object, while normal acceleration relates to the change in direction of the velocity vector during rotational motion. If the net force on an object is zero, then both acceleration and velocity remain constant. The confusion often arises in problems involving static friction and tension, where the forces may balance out but still yield a non-zero acceleration in calculations. Understanding the distinction between these types of acceleration is crucial for solving dynamics problems effectively.
Lenjaku
Messages
16
Reaction score
0
I was wondering if acceleration (a) is the speed in which speed changes how come it can b higher than 0 and still v=0?

like when there is a force pulling from the other side, the body won't move but since there is force there is acceleration.

So which is which?
Does the tangential acceleration affect the angle of the velocity vector?
and its size the speed in which the speed would change?
then what does the normal acceleration does?

It was clear at first but after solving some problems I got confused -.-
 
Physics news on Phys.org
Acceleration only occurs when there is a net force on an object. If sum of all the forces (treated as vectors) acting on an object equals zero, then there is no net force and no acceleration.
 
Lenjaku said:
... like when there is a force pulling from the other side, the body won't move but since there is force there is acceleration...

One must look at the net i.e. the resultant force acting on the body.

If this resultant force is zero then the acceleration must be also zero.
 
I had a problem where I had static friction and force in opposite directions and I had to find the time in which the object will start moving (while the force was represented with t for time).
So I went ahead and found the max static friction and found the time needed but when I tried the t I found in the general equation of ma I got a positive number.
Teh t I found works for

The force worked on another object which was tied to this 1 with idialistic rope.


-fs+T=ma
a turns to be 0.

(T for tension)

But then why the x component won't be 0 when I calculate it with t?
this is teh equation:
a(t)=0.8163*t-2.64

And there is this equation:
-fs+T=ma
T=3.63636*t
then : fs=T
fs=15.68
so t=4.31

a turned to be:0.8163*t-2.64

I don't get why it is not a 0...
a(t=4.31)=0.8163*4.31-2.64=0.878...
 

Attachments

  • ex.png
    ex.png
    8.1 KB · Views: 482
Last edited:
Could you please clarify your post and original question a little bit?
Normal acceleration and tangential acceleration are related to rotational movement.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Is My Understanding of Accelerations in Irodov 1.258 Correct?
Replies
14
Views
1K
Terminal velocity and acceleration
Replies
7
Views
882
Normal and tangential components of acceleration
Replies
21
Views
4K
Acceleration of the cart on a Ferris Wheel (Circular Motion)
Replies
11
Views
2K
Analyzing a Combination of Beer+Lower Arm for Maximum Acceleration
Replies
24
Views
2K
Elliptic path, normal and tangential acceleration
Replies
35
Views
3K
What am I Missing? Solving Conservation of Energy
Replies
7
Views
1K
Finding normal and tangential acceleration
Replies
3
Views
2K
Acceleration in uniform circular motion is uniform or non-uniform?
2
Replies
55
Views
3K
Angle between radius and acceleration
Replies
4
Views
1K

Hot Threads

Recent Insights

Back
Top