What Affects the RMS Speed Difference Between Helium Atoms and Molecules?

AI Thread Summary
The discussion focuses on calculating the new pressure of helium after its root mean square (rms) speed increases by 50% due to added heat. It highlights the relevant equation for rms speed, which is dependent on temperature and mass. A key point of confusion arises regarding whether the rms speed of helium atoms differs from that of helium molecules, with clarification that helium is a monatomic gas, thus the rms speed for both is the same. The mass of a helium atom is noted as 6.6x10^-26 kg, which is essential for calculations. Understanding these concepts is crucial for solving the homework problem effectively.
barrylwires
Messages
4
Reaction score
0

Homework Statement


Heat is added until the rms speed of a helium atom has increased 50%. Find new pressure. (Not all parameters given.)


Homework Equations


rms = (3kT/m)1/2
mass of molecule = mass of mole/NA
Then, mass of helium molecule is 6.6x10-26kg

The Attempt at a Solution


Question: Is rms speed of a helium molecule the same as the rms speed of an atom. Yes, because the atoms make up the molecule? No, helium is diatomic (right?) and so that has to be taken into account??
 
Physics news on Phys.org
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top