(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The rms speed of molecules in a gas at 20.0°C is to be increased by 1.4 percent. To what temperature must it be raised?

k = 1.38E-23 (Boltzmann's Constant)

Ratio in speed: 1.014 : 1

Ratio in Volume: 1.014² = 1.0282 : 1

T1 = 20°C = 293°K

The Volume of 1 mol of an ideal gas is 22.4 L

2. Relevant equations

v(rms) = √(3kT/m)

KE = ½mv² = 1.5kT

V1²/V2² = T1²/T2²

3. The attempt at a solution

22.4/(22.4*1.0282) = 293²/T2²

.9726 = 293²/T2²

.9726T2² = 293²

T2 = 297.103°K

Am I correct in my thinking?

Thank you.

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# Homework Help: Thermodynamics: RMS Speed of Molecules

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