What Are Common Mistakes When Calculating the Laplacian of |r|?

erb12c
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Homework Statement


Given: |r|=√(x^2+y^2+z^2) r=xi+yj+zk

(i)Find the partial derivative with respect to x of |r|.
(ii) Find the Laplacian of |r|.

Homework Equations

The Attempt at a Solution


For (i) I got x/|r|
but then for (ii) I got 2/r which I don't think is correct
 
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If ##| \vec r(x, y, z) | = \sqrt{x^2 + y^2 + z^2}##, then:

$$| \vec r(x, y, z) |_x = \frac{\partial}{\partial x} (x^2 + y^2 + z^2)^{\frac{1}{2}} = \frac{1}{2} (x^2 + y^2 + z^2)^{- \frac{1}{2}} \cdot \frac{\partial}{\partial x} (x^2 + y^2 + z^2)$$

What is the definition of the Laplacian?
 
Part i) is the warm up for part ii).
What did you do to get x/|r|?

If ##\frac{\partial}{\partial x } |r| = \frac{x}{|r|} ##, then what is ##\frac{\partial}{\partial x } \frac{x}{|r|} ##?

I think 2/|r| is right.
 
RUber said:
What did you do to get x/|r|?

If you clean up the computation in the second post:

$$\frac{1}{2} (x^2 + y^2 + z^2)^{- \frac{1}{2}} \cdot \frac{\partial}{\partial x} (x^2 + y^2 + z^2) = \frac{x}{\sqrt{x^2 + y^2 + z^2}} = \frac{x}{| \vec r |}$$

If ##\frac{\partial}{\partial x } |r| = \frac{x}{|r|} ##, then what is ##\frac{\partial}{\partial x } \frac{x}{|r|} ##?

I think 2/|r| is right.

It is, but it would be nice if the OP showed some of the work.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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