What are injective and surjective maps in vector spaces?

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SUMMARY

This discussion clarifies the definitions of injective and surjective maps in the context of vector spaces. An injective mapping ensures that no two elements in set A correspond to the same element in set B, allowing for unique element identification. Conversely, a surjective mapping guarantees that every element in set B is associated with at least one element in set A, ensuring complete coverage of set B. Understanding these concepts is essential for grasping the notion of isomorphisms in vector spaces.

PREREQUISITES
  • Understanding of basic set theory
  • Familiarity with vector spaces
  • Knowledge of functions and mappings
  • Basic concepts of linear algebra
NEXT STEPS
  • Study the properties of isomorphisms in vector spaces
  • Learn about bijective functions and their significance
  • Explore examples of injective and surjective mappings in linear transformations
  • Investigate the implications of these mappings in quantum mechanics
USEFUL FOR

Undergraduate students studying mathematics, particularly those focusing on vector spaces and linear algebra, as well as educators seeking to clarify these concepts for their students.

ylem
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Hello! I hope I've posted this in the correct section...

I'm a 3rd year undergraduate and we're currently studying Vector Spaces (in QM) and I just don't understand what injective (one-to-one) and surjective (onto) mean? As a result I have no idea what an isomorphism is!

I realize this is probably a very simple question, but I'm just struggling so much with the course!

Cheers, Samantha
 
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Ok, the first thing you have two focus on, is that you have two SETS, call them A and B.
Both A and B has elements, determinable by some criterion.


Now, a MAPPING from A to B takes each element in A and "relates" it to some unique element in B.

To say that a mapping is injective means that there are no two elements in A that are related to the same element in B. Thus, knowing the mapping procedure along with the element in B, we can DEDUCE from this what is the element in A which is related to the known element in A.
If we denote the element in B related to element x in A with f(x), this means that if f(x)=f(y), then x=y (only ONE unique element in A is related to the value of f(x))

To say that a map is SURJECTIVE means that whatever element Y in B you pick out, there exist an x in A so that Y=f(x).
The map covers B, so to speak.

Is this clear?
 
Yeah! Thanks a lot :-)
 

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