What Are the Initial and Steady State Values in an SPST Switched RLC Circuit?

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SUMMARY

The discussion focuses on analyzing the initial and steady-state values in a Single Pole Single Throw (SPST) switched RLC circuit. At time t=0-, the voltage across the capacitor, vC(0-), is 12V, and the current through the inductor, iL(0-), is 0A. At time t=0, the capacitor behaves as a voltage source, resulting in a current iC(0) of -3A and a voltage vL(0) of 12V. In the steady state at t=infinity, the capacitor acts as an open circuit, yielding vC(infinity) of 0V and iL(infinity) of 4A.

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Homework Statement


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SPST switch closes at t=0. Find vC(0-) and iL(0-), iC(0) and vL(0), and vC(infinity) and iL(infinity).

Homework Equations


The Attempt at a Solution


kind of basic circuit, i know, but i just wanted to check my answers in case i did something wrong.

At t=0- : capacitor acts like open circuit, inductor like short circuit. also there no closed loops, so there's no current. vC(0-)=V(s)=12V, and iL(0-)=0.

at t=0: capaciator behaves like voltage source, inductor like current source of 0A. so would iC(0) be -3A? and vL(0)=12V.

at t=infinity: capacitor acts like open circuit, inductor like short circuit. vC(infinity)=0V, and iL(infinity)=4A.
 
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Looks right to me
 
anyone else?? did i do this right?
 
asdf12312 said:
anyone else?? did i do this right?

Yes you did.
 

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