What Are the Key Insights of the Binomial Series Homework Statement?

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The discussion revolves around the differences between two summation expressions involving binomial coefficients. Participants clarify that the first expression, which sums over pairs where r is less than s, has fewer terms than the second expression that sums over all pairs of r and s. It is noted that the second sum effectively includes terms like C1 + C2 and C2 + C1, leading to roughly double the number of terms compared to the first sum. The conversation also touches on finding an exact equation for the difference between these two sums. Ultimately, the participants engage in deriving and simplifying the expressions related to binomial coefficients.
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Homework Statement



ue&space;of}\sum_{0\leq&space;r<&space;s\leq&space;n}\sum&space;(C_{r}&space;&plus;&space;C_{s}).gif

The Attempt at a Solution



Is there any difference between the above expression and
gif.latex?\sum_{r=0}^{n}\sum_{s=0}^{n}(C_{r}&plus;C_{s}).gif
?

Is there any relation between these two?
 
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Abdul Quadeer said:

Homework Statement



ue&space;of}\sum_{0\leq&space;r<&space;s\leq&space;n}\sum&space;(C_{r}&space;&plus;&space;C_{s}).gif

Are you sure there are up to 2 sigma signs in that expression? By the way, you mean C_r^n right?

If there's just one sigma, then \sum_{0 \le r &lt; s \le n} (C_r^n + C_s^n) is different from \sum_{r = 0}^n \sum_{s = 0}^n (C_r^n + C_s^n).

In the first sum \sum_{0 \le r &lt; s \le n} (C_r^n + C_s^n), r, and s can take any value raging from 0 to n, but r must be less than s.

However, in the second sum: \sum_{r = 0}^n \sum_{s = 0}^n (C_r^n + C_s^n), r, and s can take any value raging from 0 to n, no more requirement is needed.

So, in general, the second sum will have more terms than the first sum.
 
Hi Abdul! :smile:

The second one is roughly double the first, since it contains eg C1 + C2 but not C2 + C1.

hmm … what about all the terms such as C1 + C1 ? :rolleyes:

can you find an exact equation for the difference between the second and twice the first? :smile:
 
VietDao29 said:
Are you sure there are up to 2 sigma signs in that expression?

Yeah there are 2 sigma signs. 0<=r<s<=n is in between the two sigma signs.

tiny-tim said:
can you find an exact equation for the difference between the second and twice the first?

Does that equate to
gif.latex?\sum_{r=0}^{n}(C_{r}&space;&plus;&space;C_{r}).gif
?
 
Yes, except i'd call it 2 ∑Cr :smile:

ok now write ∑∑ (Cr + Cs) over all r and s in terms of ∑Cr :wink:

(try it first with an easy small number for n, like n = 3, if you're stuck)
 
Thanks!... I got the answer :smile:
 
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