What Are the Key Parameters for a 120-V DC Shunt Motor?

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SUMMARY

The discussion focuses on the calculations related to a 120-V DC shunt motor, specifically addressing parameters such as field current, armature current, back EMF, developed power, and torque. Key values include an armature circuit resistance of 0.2 Ω, a field circuit resistance of 60 Ω, and a full-load line current of 40 A. The user successfully solved parts (a) through (e) but sought clarification on the starting armature current and the external resistance needed to limit this current to 200% of the full-load current.

PREREQUISITES
  • Understanding of DC motor principles
  • Knowledge of electrical circuit analysis
  • Familiarity with Ohm's Law and power equations
  • Basic concepts of magnetic saturation and armature reaction
NEXT STEPS
  • Calculate the full-load developed power using the formula P = E(armature) * I(armature)
  • Determine the half-full load armature current and its implications on motor performance
  • Analyze the starting current of the armature and its significance in motor operation
  • Explore methods to calculate external resistance required to limit starting current
USEFUL FOR

Electrical engineers, students studying motor control, and professionals involved in the design and analysis of DC motors will benefit from this discussion.

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Questions about shunt motor

Homework Statement


Good evening everyone, I've got the following question :

A 120-V dc shunt motor having an armature circuit resistance of 0.2 Ω and a field circuit resistance of 60 Ω, draws a line current of 40 A at full-load. The rated full-load speed is 1800 rpm. If the magnetic saturation and armature reaction are negligible, calculate
a. The field current, If.
b. The full-load armature current, IaFL.
c. The full-load back EMF, EbFL.
d. The full-load developed power, PdFL.
e. The full-load developed torque, TdFL.
f. The half-full load armature current, Ia1/2FL(Td1/2FL= 1/2TdFL).
g. The half-full load back EMF, Eb1/2FL.
h. The motor speed at half-full load, n1/2FL.
i. The armature current at the instant of starting, Iastarting.
j. The value of the external resistance, Rext that should be connected in series with the armature winding to reduce the starting current to 200% of the full-load current.

Homework Equations





The Attempt at a Solution


Lets see,, I solved until part (e) and I didn't understand the rest.
My questions are :
(d)
Full-load developed power
, does it mean P = E(armature)*I(armature) ?? and BTW the word
developed
means output ??
(f) what does
half-full load armature current
mean ?? what should I do to make the load half ??
(i)
i. The armature current at the instant of starting, Ia(starting)
does it equal 0 ?? and if it does why and if not why not ??

these are my questions for now ,, I'll try solving (j) after solving those ,, so I need help :smile:
 
Last edited:
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OK guys ,, I solved all of them except (i) & (j) ,, how can I get the starting current of the armature ?
 

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