What are the rules for adding numbers with uncertainties?

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When multiplying a measured value of 35m by the countable number 3, the result should be expressed as 110m due to significant figures rules, as 35m has 2 significant figures and 3 is considered infinite. Alternatively, adding 35m three times also yields 105m, but this method does not increase precision. The discussion highlights that the precision of the answer does not improve by choosing addition over multiplication. It emphasizes that when adding numbers with uncertainties, the independence of the variables must be considered to avoid reinforcing errors. Ultimately, the method of calculation should align with the nature of the measurements involved.
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A measured value of 35m is being multiplied by the countable number 3 (say you went 3 times around a track that was 35m long). What's the correct number of sigfigs in the answer?

Method 1:

35 m x 3 = 105m = 110m
By significant digits rules of multiplication, this would be 110m. (The 35m has 2 sigfigs and 3 has infinite because it is a countable number)

Method 2:

35m + 35m + 35m = 105m
By significant digits rules of addition, this would be 105m (All numbers are significant to unit place)

Am I missing something? I can't imagine the precision of your answer being increased by your choice of adding the number 3 times instead of multiplying by 3.
 
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The increase in precision is a result of going around the track once and obtaining a value of 35m and then multiplying by 3 to approximate the distance traveled going around 3 times vs. going around the track 3 consecutive times and confirming the same measured value of 35m and then summing those values.
 
To put Anon0123's answer in a different way, when you add numbers with uncertainties you have to consider whether they are independent. If they are, you can suppose that you will not be so unlucky that all the errors will reinforce. I'm not sure what rule for addition you have, but I believe it will only apply to independent random variables.
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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