What Are the Solutions to bx^2 + cx + a = 0 for Any Constants a, b, and c?

AI Thread Summary
The discussion focuses on solving the quadratic equation bx^2 + cx + a = 0 for any constants a, b, and c. Participants clarify that part a requires finding the general solutions for x, while part b involves substituting specific values into the quadratic formula. The quadratic formula is confirmed as the appropriate method for obtaining solutions in part b. The conversation emphasizes that part a is a broader case applicable to any constants. Understanding the general solution is crucial for tackling specific instances of the equation.
imdapolak
Messages
10
Reaction score
0
1. Suppose y = bx^2 +cx + a
a.) in terms of a, b, and c, what values of x make y=0?

b.) if a=3.1, b= -2.2 and c=-4.3 evaluate those solutions to 3 significant digits:


Homework Equations





3. I am not really sure how to solve for what the question is asking for in part a, and for part b do I just plug those values into a quadratic formula for an answer? Any help is appreciated
 
Physics news on Phys.org


for part 'b', you would want to use the quadratic formula.
 


Part a is really very similar to part b, it is just a much more general case, which applies to any constants a, b and c. It is basically saying that for any given constants, what are the solutions to the equation:

bx^2 +cx + a = 0
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top