What Are the Two Values of b for Steady Precession in a Gyroscope?

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The discussion revolves around determining the two values of b that enable steady precession of a gyroscope with a specific setup involving a fan and a sliding block. The system is balanced at b=180mm when the fan is off, and operates at 1725 rev/min, generating a gyroscopic force of 0.286 Nm. The user has calculated the moment of inertia and the gyroscopic force but is uncertain about how to find the distance the weight must move to create the necessary torque for steady precession. The suggestion is to sum the moments about the pivot point to solve for the required distance. The conversation emphasizes the importance of understanding gyroscopic principles and torque calculations in this context.
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[Question]
Homework Statement [/b]
A special purpose fan is mounted as shown in figure Q5 (Ive attached a picture of the diagram). The motor, armature, shaft and blades have a combined mass of 2.2Kg with a radius of gyration of 60mm. The axial position of b of the 0.8kg block A can be slid on the mounting shaft. With the fan turned off, the unit is balanced about the x-axis when b=180mm

The motor and fan operate at 1725rev/min (180.6 rad/s) in the direction shown. Determine the two values of b that will produce a steady procession of 0.2rad/s about the y-axis.

[Attempt]
I have drawn a free body diagram of unit rotating due to gyroscopic forces (Attached). I worked out the moment of inertia was (60*10^-3)^2*2.2= (7.92*10^-3) kgm^2. I then worked out that the gyroscopic force generated by the fan was (7.92*10^-3)*(0.2)*(180.6)=0.286Nm. I am really confused how to work out the distance that the weight moves either towards or away from the pivot to cause this torque.
 

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Try summing the moments about R.
 
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