What are the x and y intercepts y= x+2/x-7 rational

[jeahomgrajan]

what are the x and y intercepts

y= x+2/x-7

rational expression

is y=-2/7
and x= -2

 

[sutupidmath]

you find x intercepts by letting y=0, and y intercepts by letting x=0.

 

[n!kofeyn]

you find x intercepts by letting y=0, and y intercepts by letting x=0.

That is the general approach to these problems, but notice that the function is not defined at x=0.

What do you think this means jeahomgrajan? How would you go about finding the x-intercept, i.e. setting y=0 as sutupidmath mentioned and then solving for x?

 

[sutupidmath]

That is the general approach to these problems, but notice that the function is not defined at x=0.

i interpreted the function as:


y=x+\frac{2}{x-7}

 

[n!kofeyn]

i interpreted the function as:
y=x+\frac{2}{x-7}

I see. Gotcha :) Gotta love \LaTeX.

 

[symbolipoint]

The original equation as written means exactly:

y = x + \frac{2}{x} - 7

 

[n!kofeyn]

The original equation as written means exactly:

y = x + \frac{2}{x} - 7

We know that. sutupidmath misread the original equation, and that's what that post was about. Please see my original post jeahomgrajan.

 

[HallsofIvy]

What was originally written would be strictly interpreted as
y= x+ \frac{2}{x}-7
But, considering how many people just hate to use parentheses, it could also be interpreted as "x+ 2/(x- 7)"
y= x+ \frac{2}{x- 7}
or even as "(x+2)/(x- 7)"
y= \frac{x+ 2}{x- 7}

Unfortunately, jeahomgrajan hasn't got back to say which he/she meant, but the fact that he/she suggested y= -2/7 and x= -2 as intercepts suggests what sutupidmath assumed was meant.