What Causes the Difference Between Calculated and Experimental Acceleration?

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The discussion centers on the discrepancy between calculated and experimental acceleration in a physics lab involving a car and weights. Key factors contributing to this difference include friction, which affects net force, and potential inaccuracies in timing measurements, despite using an electronic device. Human reaction time, although not the primary focus, could also influence timing if manual measurements were involved. The conversation emphasizes that while theoretical calculations assume ideal conditions, real-world experiments often yield variations due to these factors. Understanding these elements is crucial for accurately interpreting experimental results in physics.
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Homework Statement



So we did a lab this week in my physics class.

We had a car on a horizontal table, that was attached to a string with weights (The weights were over the edge of the table.) We then calculated the experimental acceleration and the calculated acceleration. These numbers were different.

My teacher asked us "What was causing the difference between the calculated acceleration and experimental acceleration..."
He also mentioned something to do with Newton's laws.

Do you know the answer/Can help me out?

HUMAN ERROR IS NOT THE ANSWER...And the the time was taken by a electronic device.

Homework Equations



g = 9.8 m/s

The Attempt at a Solution



I really don't know how to start! what's causing the difference!
 
Last edited:
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Friction, human reaction time. F = d(mv)/dt

Since friction affects net force, reaction affects time, one wouldn't expect to get the exact answer..
 
unscientific said:
Friction, human reaction time. F = d(mv)/dt

Since friction affects net force, reaction affects time, one wouldn't expect to get the exact answer..

I'm not really sure what you mean by human reaction time?

Elaborate? like ... the time that i calculated forit to go? because it was takeen by a stop watch
 
ok, human has a reaction time of about 0.19s. Which means you could have pressed the time too late, which means the time u measure is more than the the theoretically calculated time.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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