What causes the normal force to increase in circular motion?

AI Thread Summary
In circular motion, the normal force increases significantly at the bottom of the path due to the need for centripetal force, which is required to keep the object moving in a circular trajectory. As the object descends, its velocity increases, leading to a greater net force acting on it. At the bottom of the circular path, the normal force must counteract both the gravitational force and provide the necessary centripetal force, resulting in a higher normal force measurement. Once the object transitions to a straight path, the normal force returns to equilibrium with the weight of the object. This transition illustrates how forces change in different motion contexts.
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Homework Statement


Circular Motion.PNG


In my physics book (Young and Freedman 12 edition), in the chapter about conservation of energy, it teaches me that I can use the theory of conservation of energy and discover the velocity at the bottom of a circular path, having the height of this circular path. I understand and am ok with that part, however, there's another thing that I don't understand.

Suppose this image, if we calculate the velocity at the bottom, and then the net force, we will discover that the normal force is in fact applying 735 Newtons. Well, here's the thing, as soon as the circular paths ends and the "straight" path begins, the normal force will be simply equal to the weight again(245N), why does this happen? What I mean is, what in the circle magically makes the normal increase this much?
 
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As you know, a body with no forces acting on it will move at a constant speed in a straight line. To make the skater complete the arc requires a centripetal force. As the skater descends he speeds up, so the centripetal force is greatest just before the arc levels out.
 
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