What Charge Value Would Keep the Moon in Orbit by Electrical Force?

AI Thread Summary
To determine the charge value needed to keep the Moon in orbit around the Earth using electrical attraction, the equation m2v^2/r = kQ^2/r^2 should be used, where m2 is the Moon's mass and v is its orbital velocity. The user initially attempted to apply the gravitational force equation but found it unhelpful. The necessary calculations involve understanding the balance of forces between gravitational and electrical attraction. Accurate values for the Moon's velocity and constants like k (Coulomb's constant) are crucial for finding the correct charge Q. The discussion emphasizes the need for proper application of physics principles to solve the problem effectively.
acissej2487
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Here is my problem:

Suppose that electrical attraction, rather than gravity, were responsible for holding the Moon in orbit around the Earth.
If equal and opposite charges were placed on the Earth and the Moon, what should be the value of Q to maintain the present orbit? Use these data: mass of Earth=5.98*10^24 kg, mass of Moon = 7.35*10^22 kg, radius of orbit=3.84*10^8 m. Treat the Earth and Moon as point particles.


I know that I use Gm1m2/r^2 = kQ2/r^2. But I cannot get the right answer!

Help please :)
 
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I know that I use Gm1m2/r^2 = kQ2/r^2. But I cannot get the right answer!
You have to use m2v^2/r = kQ2/r^2 where m2 is the mass of the moon and v is the velocity of the moon around the earth.
 
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