What Determines the Local Extrema in Dynamical Systems?

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Discussion Overview

The discussion revolves around determining local extrema in dynamical systems, specifically through the analysis of steady states and stability of a separable differential equation. Participants explore the implications of different parameter values and the behavior of the system around equilibrium points.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants inquire about the definitions of "steady state" and "stability," suggesting these concepts are foundational to the discussion.
  • There is mention of the parameter 'a' being undefined, with suggestions to analyze cases where a<1, a=1, and a>1 separately.
  • One participant identifies three steady states at u=0, u=1, and u=-a, and expresses uncertainty about the implications of varying 'a'.
  • Another participant corrects an earlier misreading and confirms the equilibrium points as u=-a, 0, and 1, providing a detailed analysis of the behavior of the system around these points.
  • It is noted that u=-a is a local maximum, u=0 is a local minimum, and u=1 is a local maximum based on the sign of the derivative u'.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the implications of the parameter 'a' and its effect on the system's behavior, indicating that multiple views remain regarding the analysis of steady states and stability.

Contextual Notes

There are unresolved aspects regarding the definitions of stability and the specific conditions under which the behavior of the system changes, particularly related to the parameter 'a'.

mt91
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Any help would be appreciated
 
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what do you need help with? Do you know what "steady state" means? Do you know what stability is? An interesting, non-mathematical, phrase here is "biological relevance". What do you think that means? There is the parameter, a, that is undefined. You might want to consider the cases a<1, a= 1, and a> 1 separately.

Do you know what a "separable differential equation" is? This equation is "separable"- it can be written $\frac{du}{u(1- u)(a+ u)}= dt$. The left side can be integrated using "partial fractions".
 
Last edited:
Country Boy said:
what do you need help with? Do you know what "steady state" means? Do you know what stability is? An interesting, non-mathematical, phrase here is "biological relevance". What do you think that means? There is the parameter, a, that is undefined. You might want to consider the cases a<1, a= 1, and a> 1 separately.

Do you know what a "separable differential equation" is? This equation is "separable"- it can be written $\frac{du}{u(1- u)(a+ u)}= dt$. The right side can be integrated using "partial fractions".
I got 3 steady states, as u=0, u=1 and u=-a?

and then by plotting u(1-u)(a+u), indicated from the graph that u=-a is stable, u=0 is unstable and u=1 is stable. Not sure what you mean by looking at the cases for a, so are you ok to explain that?
 
That was because I had misread the problem and was looking at u= -1, 0, and -a!

Yes, the equilibrium points are at u= -a, 0, and 1. We can write u'= (u+ a)u(1-u)= (-1)(u+ a)u(u- 1). if u< -a then all four of those are negative so the product, and so u', is positive. u is increasing up to u(-a). If -a< u< 0 then -1, u, and u-1 are negative but u+ a is positive so the product, and so u', is negative. u goes down from u(-a) to u(0). If 0< u< 1, both u+ a and u are positive while -1 and u are negative so the product, and so u', is positive. u goes up to u(1). Finally, for u> 1, all except -1 are negative so u' is negative. u goes down from u(1).

That is, u goes up to u(-a) then down after that so u(-a) is a local maximum. u goes down to u(0) then up so u(0) is a local minimum. u goes up to u(1) then down so u(1) is a local maximum.
 

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