What did I do wrong in this Bessel equation?

yungman
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I need to convertx^{2}y''+2xy'+[kx^{2}-n(n+1)]y=0 using y=x^{-\frac{1}{2}}w to a normal Modified Bessel Equation and I cannot get to that. I check many times and I must be having a blind spot!

This is my work:

y=x^{-\frac{1}{2}} w \Rightarrow y'=-\frac{1}{2}x^{-\frac{3}{2}}w+x^{-\frac{1}{2}}w' \Rightarrow y''=\frac{3}{4}x^{-\frac{5}{2}}w-\frac{1}{2}x^{-\frac{3}{2}}w'+x^{-\frac{1}{2}}w''-\frac{1}{2}x^{-\frac{3}{2}}w'

x^{2}y''+2xy'+(kx^{2}-n(n+1))y=0 \Rightarrow

[\frac{3}{4}x^{-\frac{1}{2}}w-\frac{1}{2}x^{\frac{1}{2}}w'+x^{\frac{3}{2}}w''-\frac{1}{2}x^{\frac{1}{2}}w']+[2x^{\frac{1}{2}}w'-x^{-\frac{1}{2}}w]+[kx^{\frac{3}{2}}w-n(n+1)x^{-\frac{1}{2}})w]=0


Grouping w'', w' and w terms:

x^{\frac{3}{2}}w''+(-x^{\frac{1}{2}}+2x^{\frac{1}{2}})w'+(\frac{3}{4}x^{-\frac{1}{2}}-x^{-\frac{1}{2}}+kx^{\frac{3}{2}}-n(n+1)x^{-\frac{1}{2}})w=0

Multiply by x^{\frac{1}{2}} This give:

x^{2}w''+xw'+(\frac{3}{4}-1+kx^{2}-n(n+1))w=0

I can't get the standard Modified Bessel equation because the 3/4-1 in the w term cannot be cancel out.
Please tell me what I did wrong.

Thanks
Alan
 
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Your arithmetic is correct (except that in the first line you have an exponent -\frac23 that should be -\frac32, but later steps are correct).

Is there any reason why the n (order) in the equation you end up with is required to be the same you began with? I notice that your problematic constant term is -n^2 - n - \frac14, which factors nicely.
 
ystael said:
Your arithmetic is correct (except that in the first line you have an exponent -\frac23 that should be -\frac32, but later steps are correct).

Is there any reason why the n (order) in the equation you end up with is required to be the same you began with? I notice that your problematic constant term is -n^2 - n - \frac14, which factors nicely.

You are right, I was blind! The final equation is with (n+\frac{1}{2})^{2}!

It must be old age! I read the final equation wrong and I just kept concentrate on what I did and never look at the final equation! Wasted almost an hour on this! The only excuse I can come up is I am 56! Too old!:rolleyes: BUT I am not old enough to conceed to you guys yet!

Thanks a million.

Alan
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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