sawer
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I know that\oint \vec E \cdot \vec{dS} in Gauss Law indicates electric flux.
\oint \vec E \cdot \vec{dS} = \frac{Q_{enc}}{\varepsilon_0}
But what does B.dl indicate in Ampere's Law?
##\oint \vec{B} \cdot \vec{dl} ## = ??
\oint \vec E \cdot \vec{dS} = \frac{Q_{enc}}{\varepsilon_0}
But what does B.dl indicate in Ampere's Law?
##\oint \vec{B} \cdot \vec{dl} ## = ??
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