What does det mean in physics and math?

  • Thread starter Thread starter Sicktoaster
  • Start date Start date
  • Tags Tags
    Mean
AI Thread Summary
In physics and mathematics, "det" refers to the determinant of a matrix, which is essential for solving systems of linear equations and inverting square matrices. While calculating the determinant is important, it is not always necessary for finding an inverse; methods like Gauss-Jordan elimination can be used without it, especially if the matrix is invertible. If the determinant equals zero, the matrix does not have an inverse. Understanding determinants is crucial for anyone pursuing advanced studies in math, physics, or engineering. Familiarity with matrices and determinants is foundational for further learning in these fields.
Sicktoaster
Messages
6
Reaction score
0
I'm new to physics and I see "det" used in math a lot. What does it mean?
 
Mathematics news on Phys.org
It means to take the determinant of a matrix.
 
  • Like
Likes PFuser1232
Yeah, a matrix is a rectangular arrangement of numbers and the details means taking the determinant. Look up matrices and determinants on the net. Or better yet, there's a good course in linear algebra on iTunes u ( the one with Gilbert Strang) check it out
 
The "determinant" of a matrix is mostly used to solve systems of linear equations. It has multiple uses, but most notably, finding the determinant is a crucial step in inverting a square (##n \times n##) matrix. If you plan on pursuing high level math, physics, or engineering, you'll need to know what the determinant is and how to interpret it.
 
AMenendez said:
finding the determinant is a crucial step in inverting a square (##n \times n##) matrix

Is it?
 
AMenendez said:
finding the determinant is a crucial step in inverting a square (##n \times n##) matrix
Borek said:
Is it?
I agree with Borek here (in his questioning of your statement about the determinant being a crucial step in inverting a matrix.

Certainly if det(A) = 0, the inverse of A doesn't exist, but for an invertible matrix A, you can find the inverse using Gauss-Jordan without ever taking the determinant. If it turns out that A isn't invertible, the Gauss-Jordan process will end up with a matrix with one or more rows of zeros (instead of the identity matrix) on the left side of your augmented matrix.
 
That makes sense. I'm a first-year undergrad and the highest level of math I've had is linear algebra, so I'm just pulling out of the bag of tricks I have so far. Thanks for pointing that out.
 

Similar threads

Replies
4
Views
2K
Replies
9
Views
3K
Replies
13
Views
3K
Replies
13
Views
289
Replies
6
Views
2K
Replies
4
Views
2K
Replies
2
Views
2K
Replies
5
Views
3K
Replies
26
Views
3K
Replies
12
Views
316
Back
Top