What Does \left[ z^{n} \right] (ln(1-z))^{2} / (1-z)^{m+1} Represent?

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I need help with solving this weird equation...

What is:
\left[ z^{n} \right] (ln(1-z))^{2} / (1-z)^{m+1}?
 
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Can't have an equation without an equals sign. Ahyup.
 
Can you do these two Taylor series (at 0): (ln(1-z))^2 and 1/(1-z)^{m+1} ?
Then take the product of the two series.
 
Meekah said:
I need help with solving this weird equation...

What is:
\left[ z^{n} \right] (ln(1-z))^{2} / (1-z)^{m+1}?
Please restate your question. This is not an equation, it is an expression. What are you trying to do with it?
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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