What does the ellipse tell me?

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Homework Help Overview

The discussion revolves around the intersection of a sphere defined by the equation x²+y²+z²=4 and the plane y=z. Participants are exploring the implications of the resulting equation, which is suggested to represent an ellipse.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the interpretation of the resulting equation after substitution, questioning whether it represents points of intersection or a circle. There is also a debate about the nature of the intersection and the implications of the geometry involved.

Discussion Status

The discussion is active, with participants providing different interpretations of the geometric situation. Some guidance has been offered regarding the nature of the intersection, but there remains uncertainty about the correct interpretation of the results.

Contextual Notes

Some participants express a lack of foundational knowledge in geometry, indicating potential gaps in understanding the concepts being discussed.

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Homework Statement



intersection [tex]x^2+y^2+z^2=4[/tex] and plane [tex]y=z[/tex]

Homework Equations



n/a

The Attempt at a Solution



so, i solve it simultaneously, and get the equation of ellipse [tex]x^2+2y^2=4[/tex]. but what does the ellipse tell me? is that the points of the intersection?, but aren't it should be a circle?
 
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First, that's not the equation for an elipse. I would be ((x^2)/4)+((y^2)/2)=1. Then set y=0 to find the intercepts. You can use the first equation you found to do that easily, you'll get [tex]\pm[/tex]2.
 


the first equation is the equation for a sphere of radius 2, and any plane thorugh the origin will intersect it in a circle

after substituting y=z, the equation you get is that of an ellipse projected onto the xy plane, but remember you have the extra z coordinate, so in the y=z plane it is still a circle
 


Yeah, that's right, but the method he did still works. Just the substitution changes things. Checked on wolframalpha and it is x=[tex]\pm[/tex]2
 


why do you get 2 points? it should be the equation of a circle shouldn't it?
 


i messed up, don't have basics on geometry, maybe i should read first some on plane and sphere. later i show my work
 


i think what you did is ok, just missed a bit on interpretation at the end
 

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