What Does the Integral of Consumption Profiles Represent in Economics?

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Homework Help Overview

The discussion revolves around the interpretation of an integral related to consumption profiles in economics, specifically focusing on the expression for total consumption \( C_t \) derived from individual consumption \( C_t(i) \). Participants are exploring the meaning of the integral from zero to one and its implications for understanding consumption behavior.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants are attempting to clarify the meaning of \( C_t \) and the significance of integrating \( C_t(i) \) over the interval from zero to one. Questions arise about the mathematical representation and the interpretation of the parameter \( \epsilon \). There is also a discussion about the relationship between the integral and summation notation.

Discussion Status

There is an ongoing exploration of the concepts involved, with some participants providing interpretations of the integral as a representation of consumption preferences. Guidance has been offered regarding the mathematical notation and potential interpretations, but no consensus has been reached on the implications of the integral.

Contextual Notes

Participants note the complexity of the expression and its potential relation to utility functions in economics. There is an acknowledgment of the need for further context to fully understand the implications of the integral and the parameters involved.

beaf123
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1. Homework Statement

Ct= (∫0 1 (Ct(i) ̂(1-1/ε)) di)^ (ε/ε-1)

So Ct (i) denotes number of good i consumed by the household.

But what is Ct ? What does it mean to take the intgral from zero to 1 for all the Ct (i) ?

Homework Equations

The Attempt at a Solution

 
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beaf123 said:
1. Homework Statement

Ct= (∫0 1 (Ct(i) ̂1-1/ε) di)^ ε/ε-1

So Ct (i) denotes number of good i consumed by the household.

But what is Ct ? What does it mean to take the intgral from zero to 1 for all the Ct (i) ?

Homework Equations

The Attempt at a Solution

Here is what is meant by what you wrote:
Ct = \frac{1}{\epsilon} \left( \int_0^1 \left( Ct(i)^1 - \frac{1}{\epsilon} \right) \ di \right)^{\epsilon} -1
It that really what you meant?
 
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Sorry, I added some paranthesis so it should be right now. How do write math the way you do?
 
beaf123 said:
Sorry, I added some paranthesis so it should be right now. How do write math the way you do?

I use LaTeX.

What you wrote now has exponent ##\epsilon/\epsilon - 1##. Did you mean ##\epsilon/(\epsilon-1)##? If so, use parentheses around the terms in the denominator, like this: ε/(ε-1).

Remember, when you are writing in plain text, a+b/c-d means ##a+\frac{b}{c}-d##, while (a+b)/(c-d) means ##\frac{a+b}{c-d}##.

Anyway, you now (probably) have:
<br /> Ct = \left( \int_0^1 \left( Ct(i)^{(\epsilon-1)/\epsilon} \right) \ di \right)^{\epsilon/(\epsilon-1)}
What is ##\epsilon##?
 
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Good question. From what I understand it says something about consumption preferences. And it is presented in the complicated way to give a more meaningful expression later.

What I now know is that this is simmilar to a sum and you could use sum notation to present the same and ( can it be correct?) that the integral from 0 to 1 is another way of saying the integral from 0 to infinity.

So gbasically my interpretation now boils down to Ct being some sort of sum of all the small c`s, in other words an index.

And yes, your new expression is the one I meant.
 
beaf123 said:
Good question. From what I understand it says something about consumption preferences. And it is presented in the complicated way to give a more meaningful expression later.

What I now know is that this is simmilar to a sum and you could use sum notation to present the same and ( can it be correct?) that the integral from 0 to 1 is another way of saying the integral from 0 to infinity.

So gbasically my interpretation now boils down to Ct being some sort of sum of all the small c`s, in other words an index.

And yes, your new expression is the one I meant.

I don't know the context of your problem, but I can give a possible interpretation (and which is possibly wrong). You have some kind of "consumption profile" ##Ct(i), 0 \leq i \leq 1##, and a "utility function" for consumption of the form ##u(c) = c^{\alpha}##; it happens that ##\alpha = (\epsilon-1)/\epsilon## in your case, but never mind that for now.

Anyway, the total utility for the consumption profile is ##U(Ct) = \int_0^1 u(Ct(i)) \, di = \int_0^1 Ct(i)^{\alpha}\, di##. The quantity ##U(Ct)^{1/\alpha}## is the "utility-equivalent" consumption, which is the single consumption level ##C_{\alpha}## that has the same utility as the profile ##\{ Ct \}##. That is the quantity computed in your post.

I don't know if that really means anything, but it is similar to the type of thing that people look at in Finance, when they talk about "certainty equivalents" for risky investments, for example.
 

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