What Does the Ratio sin(φ1)/sin(θ4) Reveal About Light Refraction?

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Discussion Overview

The discussion revolves around the ratio sin(φ1)/sin(θ4) in the context of light refraction through multiple transparent materials with different refractive indices. Participants explore the dependencies of this ratio on various refractive indices and angles, engaging in both mathematical reasoning and conceptual clarification.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents a question about what the ratio sin(φ1)/sin(θ4) depends on, listing several options related to refractive indices.
  • Another participant suggests that the original poster should compute the answer themselves, implying that the solution involves basic fraction multiplication.
  • A different participant encourages a deeper engagement with the definition of refractive index and the angles involved, hinting that a simpler answer exists than initially thought.
  • One participant notes that the simple answer is not among the provided options and discusses the concept of horizontal phase advance being consistent across different media, suggesting that the angle of the ray is controlled by the local refractive index.
  • Another participant reiterates the importance of understanding the horizontal advance of phase and provides an analogy involving wave fronts to clarify this concept.

Areas of Agreement / Disagreement

Participants express differing views on the correct interpretation of the ratio and its dependencies, with no consensus reached on the specific answer or the implications of the ratio in the context of refraction.

Contextual Notes

Some participants' arguments depend on assumptions about the behavior of light at interfaces and the definitions of refractive indices, which remain unresolved in the discussion.

Misr
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[PLAIN]http://img843.imageshack.us/img843/6831/dsc00723mm.jpg
a light ray falls on parallel layers made of transparent materials which have different refractive indicies
so ,what does the ratio sin(fi 1)/sin(theta 4) depend on?
1-n1,n2
2-n2,n3.n4
3-n1,n2,n3,n4,n5
4-n1,n2
could you explain the right answer to me?
 
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Maybe you should compute it by yourself? I believe you are able to multiply fractions with proper cancellation.
 
Get stuck into the thing, using the definition of refractive index and the successive angles on the way through. If you are careful, you will find it gives you a very much simpler answer than you might imagine!
 
What's more, the simple answer is not one of the ones given! (Since 1 and 4 are repeated, I'm guessing 4 was supposed to be n1, n5). If you don't feel that multiplying fractions is sufficiently general to count as an "explanation", just note that the horizontal advance of phase is the same in all 5 media, as that does not change across any of the boundaries (or even with a continuous variation of n). Thus the angle of the ray depends only only on the contrast of the rate of horizontal advance of phase, and vertical advance of phase. But the rate of advance of phase along the direction of the ray depends only on the local value of n, so the angle of the ray is always controlled entirely by its local n value. Thus any contrast between original and final directions must be dependent only on...
 
Maybe you should compute it by yourself? I believe you are able to multiply fractions with proper cancellation.
Get stuck into the thing, using the definition of refractive index and the successive angles on the way through. If you are careful, you will find it gives you a very much simpler answer than you might imagine!

Matimatically is okay since theta1=fi2 so their sin would be cancelled
so
sin(fi 1)/sin(theta 4)=n1\n5 right?
If you don't feel that multiplying fractions is sufficiently general to count as an "explanation"
That's it!
horizontal advance of phase
what do u mean by this?
 
Misr said:
what do u mean by this?
Think of the wave as rows of wave fronts, like crests of water waves in straight lines. Now imagine one of the interfaces between the different media, and imagine how one of those wave fronts (or wave crests) would move along that horizontal surface (ignore all else, just think about how that wave crest travels along that interface). The wave crest is a point of fixed phase, call it phase=0 at the crest if you like, and that point of phase=0 moves along the interface at some speed. It doesn't matter what that speed is right now, what matters is that it is the same speed for the wave on either side of the interface-- it's the same speed for the incoming wave in n1, for example, as for the outgoing wave in n2, because it's just moving along the interface between n1 and n2. Now there is also a speed that the wave front itself moves, diagonally, through n1 and through n2, but that speed is different in the two media (it scales like 1/n). That is the speed that the phase=0 advances along the direction that the wave is actually moving, but how could it be different in the two media, yet have the same horizontal speed component (along the interface and everywhere else too)? The same way any varying speed can have the same horizontal component-- by changing its direction! That is the "reason" that the wave changes direction when n changes, which is called refraction.
 

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