Understanding Matrices and GL(n,R) Functions

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Two things:

1) If we say that the space of all 2 by 2 matrices is identified with R^4, what does that mean?

2) Suppose f is a function from GL(n, R) to GL(n, R) (the space of all real n by n invertible matrices) identified with \mathbb{R}^{n^2} I am asked to prove that df_{A_0} (X) = -X where A_0 is the identity matrix. My question is, df_{A_0} would usually denote that derivative of f at the point A_0, so where does that (X) part come into play?

I know that I should be asking my prof this, but I want to do these homework questions before my next class (Wednesday), so it would be great if you guys could help me out.
 
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For the first question: a (real) 2 by 2 marix is specified by four numbers, which defines a point in R^4.

Second question: I am not familiar with the notation.
 
For the second question: The derivative of a function is a linear function. In this case the question is asking you to prove that the linear function that the derivative is is the function df(X)=-X
 
OfficerShredder, I was thinking that. But usually my prof would use the notation df_{A_0} to denote the derivative of f at A_0. Why add in the extra (X) ?

And mathman, do I read off the entries of the matrix row by row or column by column
 
In case it helps, OfficerShredder, f is defined by f(A) = A^{-1} if A \in GL(n,r)
 
JG89 said:
And mathman, do I read off the entries of the matrix row by row or column by column
That's up to you. You can identify the space of nxm-matrices with R^{mn} in a lot (namely (nm)!) of ways, there's not really a preferred way.
 
JG89 said:
OfficerShredder, I was thinking that. But usually my prof would use the notation df_{A_0} to denote the derivative of f at A_0. Why add in the extra (X) ?

And mathman, do I read off the entries of the matrix row by row or column by column
For the same reason that to talk about the "squaring function" we say f(x)= x^2 rather than just "f= ( )^2". A function is defined by what it does to values of x.
 
I'm still not getting it. In my prof's usual notation df_{A_0} would mean the derivative of f at A_0. If you write it using the prime notation, df_{A_0} = f'(A_0). I still don't see why you would need the matrix X when we're evaluating the derivative function at the point A_0
 
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lol nevermind guys. I totally forgot that my proof uses that notation to mean the directional derivative of f at the point X with respect to A_0
 
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