What Force Is Needed to Roll a Wheelchair Over a Curb?

  • Thread starter Thread starter AriAstronomer
  • Start date Start date
  • Tags Tags
    Moment
Click For Summary
SUMMARY

The discussion focuses on calculating the force required to roll a wheelchair over a curb, specifically addressing the moment arm involved in the process. The main wheel's radius (r) and the curb height (h) are critical variables in determining the force (F) applied at point P. The moment arm is defined as the x component, calculated as d = [r^2 - (r-h)^2]^1/2, rather than simply the radius. Additionally, the force's effective distance is represented as the y component, or 2r - h, emphasizing the importance of understanding the geometry of the situation.

PREREQUISITES
  • Understanding of basic physics concepts, particularly forces and moments.
  • Familiarity with the geometry of circles, specifically regarding wheel radius and curb height.
  • Knowledge of equilibrium conditions in static systems.
  • Ability to interpret and analyze free-body diagrams.
NEXT STEPS
  • Study the principles of torque and moment arms in physics.
  • Learn how to construct and analyze free-body diagrams for complex systems.
  • Explore the application of equilibrium equations in real-world scenarios.
  • Investigate the effects of different wheel sizes and curb heights on the required force.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as engineers and designers working on mobility aids and wheelchair design.

AriAstronomer
Messages
46
Reaction score
1

Homework Statement


(a) Estimate the magnitude of the force F a person must apply
to a wheelchair’s main wheel to roll up over a sidewalk
curb (Fig. 12.11a). This main wheel, which is the one that
comes in contact with the curb, has a radius r, and the height
of the curb is h.


Homework Equations





The Attempt at a Solution


The solution is given in the book. The thing I am stuck on is understanding the moment arm. A diagram is attached.

Apparently the moment arm to from P to O is the x component - d = [r^2 - (r-h)^2]^1/2, why wasn't it just the radius r??
Same thing goes for F - I would have thought it would just a direct line connecting P to C (the Force), but instead they say it's just the y component, or 2r - h. Why?

Ari
 

Attachments

  • diagram.jpg
    diagram.jpg
    16.2 KB · Views: 616
Physics news on Phys.org
The moment of a force about a point is the force times the perpendicular distance from the line of action of the force to that point. When the wheel jumps the curve, the wheel at point Q leaves the ground, and thus there is no force there from the ground. All the forces required from equilibrium , required to balance the wheels weight and the applied force F, are are at P, both vertically and horizontally. Try summing moments about P instead of 0.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 42 ·
2
Replies
42
Views
4K
  • · Replies 8 ·
Replies
8
Views
8K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
4K
Replies
3
Views
1K
Replies
7
Views
2K