What Happens Below the Planck Length?

robertjford80
Messages
388
Reaction score
0
This comes from Alex Vilenskin's Many Worlds in One:

Similarly, the gravitational interaction can be pictured as an exchange of gravitational field quanta, called gravitons. And indeed, this description works rather well, as long as the interacting particles are far apart. In this case, the gravitational force is weak and the spacetime is nearly flat. (Remember, gravity is related to the curvature of spacetime.) The gravitons can be pictured as little humps bouncing between the particles in this flat background.
At very small distances, however, the situation is completely different. As we discussed in Chapter 12, quantum fluctuations at short distance scales give the spacetime geometry a foamlike structure. We have no idea how to describe the motion and interaction of particles in such a chaotic environment.
The picture of particles moving through a smooth spacetime and shooting gravitons at one another clearly does not apply in this regime. Effects of quantum gravity become important only at distances below the Planck length

I didn't think there was such a distance below the Planck length.
 
Physics news on Phys.org
The Planck length is not a lower limit, but just a convenient (or inconvenient) unit of length.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top