What happens if the angle < Brewster's angle?

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garylau
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Sorry
i have question for TM polarization.
i don't understand why if the angle < brewster's angle,then the reflected light will experience an pi phase shift?
can anybody explain why?
 
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  • Handwritten notes on a lecture slide: "re-arranging gives tan θB = n2/n1. Note that at angles smaller than θB the reflected light experiences a π phase shift, -1 = e^(iπ)."
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Take a look at these equations, especially ##r_p## which is the (complex) reflection coefficient for TM polarization. In particular, you will be interested in the so-called internal reflection, that is when ##n_2 < n_1##.