What Happens When Ice Meets Steam?

  • Thread starter Thread starter phyter
  • Start date Start date
  • Tags Tags
    Heat
AI Thread Summary
When 1 kg of ice at 0 degrees Celsius is mixed with 1 kg of steam at 100 degrees Celsius, heat transfer occurs, leading to a phase change. The ice absorbs heat to melt into water, while the steam releases heat to condense into water. The specific latent heats and heat capacities are crucial for calculating the final temperature of the mixture. The resulting mixture will consist of water at a temperature that can be determined by balancing the heat lost and gained. Ultimately, the final state will be a mixture of water at a temperature between 0 and 100 degrees Celsius.
phyter
Messages
1
Reaction score
0
Excuse me, I have a question about heat.

1kg of 0 degree celsius ice is mixed with 1kg of 100 degree celsius vapour, what is the final temperature? What is the state of the mixture?
[specific latent heat of fusion=334000J/kg
specific latent heat of vapourization=2260000J/kg
specific heat capacity of water=4200J/kg]
Use the information above if necessary, you can also use the information which is not provided above(eg. specific heat capacity of ice, specific heat capacity of vapour etc.)
 
Physics news on Phys.org
Do not double post!
 
Please consider the following equation:

mass of water * c of water * change of temperature of water = mass of water * c of water * change of temperature of water + mass of ice * specific latent heat of fusion
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Specific heat capacity and latent heat
Replies
2
Views
242
I try to solve a thermodynamics problem on heat transfer
Replies
3
Views
2K
Heat question -- Ice cube in a cup of water....
Replies
7
Views
9K
Solving 0.02 kg Ice and 0.10 kg Water at 0°C to Melted State
Replies
8
Views
3K
Calculating Equilibrium Temperature of Ice and Water Mixture
Replies
1
Views
2K
Meteor impact - Heat vaporization and capacity
Replies
4
Views
3K
Calculate change in entropy per minute.
Replies
4
Views
1K
Final Temperature and Time to Reach it When Adding Ice to Rum and Coke
Replies
12
Views
2K
Piece of iron put into container with ice
Replies
4
Views
1K
Problem Solving - Calculate the mass of steam condensed
Replies
6
Views
5K

Hot Threads

Recent Insights

Back
Top