What identity is this? (Division to multiplication )

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Homework Help Overview

The discussion revolves around the identities related to division and multiplication, specifically exploring the transformation of expressions like a/b to ab and A^2/B^2 to (A^2)(B^2).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the nature of identities involving division and multiplication, questioning whether such transformations exist. Some suggest the relationship between division and multiplication through reciprocal values, while others introduce iterative methods for division.

Discussion Status

Participants are actively discussing various interpretations of the identities in question. Some have offered insights into reciprocal relationships and iterative methods, while others express uncertainty about the original poster's intent.

Contextual Notes

There appears to be a lack of clarity regarding the original poster's question, as well as the specific identities being sought. The discussion includes references to mathematical methods that may not directly relate to the identities mentioned.

musiclover55
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This isn't a homework help issue, I just want to know what identity(?) this is.

a/b to ab

or A^2/B^2 to (A^2)(B^2)
 
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musiclover55 said:
This isn't a homework help issue, I just want to know what identity(?) this is.

a/b to ab

or A^2/B^2 to (A^2)(B^2)
There is no identity that converts a/b to ab, nor is there one to convert A2/B2 to A2B2.

What you might be thinking of is this one:

$$ \frac{a}{b} = a \cdot \frac{1}{b}$$

In other words, dividing by a number b is the same as multiplying by the reciprocal of b (1/b).
 
Mark44 said:
What you might be thinking of is this one:

$$ \frac{a}{b} = a \cdot \frac{1}{b}$$

Or maybe this one:$$
\frac a {\frac 1 b} = ab$$
 
Although this probably isn't what you're looking for, there is a way to implement division or more specifically 1/b by iterating multiplications and additions via Newton Raphson method, but this seems unlikely to be what you're looking for.

For 1/b the iternation is:

xi+1 = xi (2 - b xi)

This converges quadratically. For integers, usually a table of bytes is used to get the initial approximation.
 
Yea, thanks everyone. I thought that was possible, but obviously it's not lol.
 
Yet another possibility: A/B= AB-1
 

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