What Integration Technique to Use for \int\sqrt{x^2-1}dx

  • Thread starter Thread starter Abraham
  • Start date Start date
  • Tags Tags
    Integration
Click For Summary

Homework Help Overview

The problem involves finding the integral of the function \(\int\sqrt{x^2-1}dx\), which falls under the subject area of calculus, specifically integration techniques.

Discussion Character

  • Exploratory, Assumption checking, Mixed

Approaches and Questions Raised

  • The original poster attempts u-substitution but expresses uncertainty about its effectiveness. Some participants suggest alternative substitutions, such as \(x = \tan(u)\) and \(x = \sec(u)\), while others propose integration by parts. There is a discussion about the appropriateness of these methods and the complexity involved.

Discussion Status

Participants are exploring various integration techniques and sharing hints without providing complete solutions. There is an ongoing dialogue about the effectiveness of different approaches, but no consensus has been reached regarding the best method to use.

Contextual Notes

The original poster mentions trying to teach themselves calculus II, indicating a potential gap in experience with integration techniques. There are also hints of tension regarding the sharing of hints versus solutions.

Abraham
Messages
68
Reaction score
0

Homework Statement



Solve:

[tex]\int\sqrt{x^2-1}[/tex]dx

Homework Equations



This is where I need help. What integration technique do I use? u-substitution? Integration by parts? None seem to work. As an added note, I've been trying to teach myself some calculus II work over the summer, so I just need a pointer in the right direction. Thank you

The Attempt at a Solution



I attempted to use u-substitution. I don't think this is the right method. Does anyone know the correct method? It got pretty messy, but I didn't get the right answer:

[tex]\int[/tex][tex]\sqrt{x^{2}+1}[/tex]dx


u = [tex]x^{2}[/tex]+1
du = 2x
x = [tex]\sqrt{u-1}[/tex]



= [tex]\frac{1}{2}[/tex] [tex]\int[/tex]([tex]\sqrt{u}[/tex])([tex]\sqrt{u-1}[/tex]) du


= ? Is this the correct start?
 
Physics news on Phys.org
Try tan(u) = x as the substitution.
 
Let I = [tex]\int\sqrt{x^2-1}[/tex]dx

Try integrating by parts.

I = [tex]x\sqrt{x^2-1}dx[/tex] - [tex]\int x\x^{2} / \sqrt{x^2-1}dx[/tex]

See if you can carry on from here.
 
I KNOW this will work. Sub x as sec(u). Go on from there.
 
physicsnoob93 said:
I KNOW this will work. Sub x as sec(u). Go on from there.

What are you implying sir? I'm sure all of us here know how to complete the problem easily. I didn't want to solve the problem for him. Therefore I gave him a hint so that he could carry on from there.
 
anirudh215 said:
What are you implying sir? I'm sure all of us here know how to complete the problem easily. I didn't want to solve the problem for him. Therefore I gave him a hint so that he could carry on from there.

Sorry, I didn't mean to offend anyone. And I didn't mean your hint was worthless.
 
physicsnoob93 said:
Sorry, I didn't mean to offend anyone.

It's cool. :smile:
 

Similar threads

  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
9
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K