What Integration Technique to Use for \int\sqrt{x^2-1}dx

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Homework Statement



Solve:

[tex]\int\sqrt{x^2-1}[/tex]dx

Homework Equations



This is where I need help. What integration technique do I use? u-substitution? Integration by parts? None seem to work. As an added note, I've been trying to teach myself some calculus II work over the summer, so I just need a pointer in the right direction. Thank you

The Attempt at a Solution



I attempted to use u-substitution. I don't think this is the right method. Does anyone know the correct method? It got pretty messy, but I didn't get the right answer:

[tex]\int[/tex][tex]\sqrt{x^{2}+1}[/tex]dx


u = [tex]x^{2}[/tex]+1
du = 2x
x = [tex]\sqrt{u-1}[/tex]



= [tex]\frac{1}{2}[/tex] [tex]\int[/tex]([tex]\sqrt{u}[/tex])([tex]\sqrt{u-1}[/tex]) du


= ? Is this the correct start?
 
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Let I = [tex]\int\sqrt{x^2-1}[/tex]dx

Try integrating by parts.

I = [tex]x\sqrt{x^2-1}dx[/tex] - [tex]\int x\x^{2} / \sqrt{x^2-1}dx[/tex]

See if you can carry on from here.
 
I KNOW this will work. Sub x as sec(u). Go on from there.
 
physicsnoob93 said:
I KNOW this will work. Sub x as sec(u). Go on from there.

What are you implying sir? I'm sure all of us here know how to complete the problem easily. I didn't want to solve the problem for him. Therefore I gave him a hint so that he could carry on from there.
 
anirudh215 said:
What are you implying sir? I'm sure all of us here know how to complete the problem easily. I didn't want to solve the problem for him. Therefore I gave him a hint so that he could carry on from there.

Sorry, I didn't mean to offend anyone. And I didn't mean your hint was worthless.
 
physicsnoob93 said:
Sorry, I didn't mean to offend anyone.

It's cool. :smile: