What integration technique to use?

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Homework Help Overview

The discussion revolves around evaluating the integral \int_0^1 dx \frac{x^{m-1}}{\ln x} where m is a positive integer. Participants are exploring various integration techniques and the implications of their choices.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the substitution method and the exponential integral function, questioning the feasibility of finding an elementary anti-derivative. There is mention of differentiation under the integral sign as a potential technique. Some participants also reflect on the correct formulation of the integral with respect to the parameter m.

Discussion Status

The discussion is active, with participants providing insights and corrections to each other's approaches. There is recognition of the complexity involved in evaluating the integral and the need to consider constants associated with the integrals. Multiple perspectives on the problem are being explored, but no consensus has been reached.

Contextual Notes

Participants note the importance of correctly setting up the integral and the potential for confusion regarding the bounds and parameters involved. There is an acknowledgment of the challenges posed by the logarithmic function in the denominator.

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Homework Statement


What technique should I use to evaluate

\int_0^1 dx \frac{x^{m-1}}{\ln x}

where m is a positive integer

?

Homework Equations


The Attempt at a Solution

 
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x^{m-1}=x^{m}\times x^{-1}
 
Don't go around trying to find the anti-derivative of that in elementary functions, the indefinite integral evaluates to Ei (m \ln x) + C, \frac{d}{dx}C = 0 where Ei(x) is the exponential integral. This result follows because after the substitution u= ln x, the original integral becomes \int^0_{-\infty} \frac{ (e^u)^m}{u} du.

Best you can do is to get an infinite series solution.
 
Last edited:
Ahh I think I've found out how to solve it, because those bounds looked quite nice =] Try Differentiation under the integral.
 
Yes. That works. My original question was a mistake, however. I wanted to use parameter differentiation to find

H(m) = \int_0^1 dx \frac{x^{m}}{\ln x}

So, I differentiated erroneously and got

H(m) = \int_0^1 dx (m-1)\frac{x^{m-1}}{\ln x}

instead of

H(m) = \int_0^1 dx x^{m}

By, the way, H(m) = \ln{m+1}.
 
Ah no it's not as easy as that...You have forgotten to deal with the Constant associated with the integrals..
 
Well I might as well give another clue, try looking at H(-1) to evaluate the constant. If my mind was a bit clear yesterday, I could have told you that; looking at the natural logs series between 0 and 1, that integral is...
 

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