What is a non-rectifiable bounded closed set in \mathbb{R}?

  • Thread starter Thread starter GreyZephyr
  • Start date Start date
  • Tags Tags
    Sets
GreyZephyr
Messages
6
Reaction score
0

Homework Statement


I am trying to work my way through Analysis on manifolds by Munkres. Question 14.5 has me stumped. Any hints on how to tackle it would be appreciated. The question is:

Find a bounded closed set in \mathbb{R} that is not rectifiable

Homework Equations



A subset S of \mathbb{R} is rectifiable iff S is bounded and the boundary of S has measure zero.

The boundary of an interval in \mathbb{R} has measure zero.

The Attempt at a Solution



I think I need a closed set who's boundary does not have measure zero. I presume it has to be an uncountable union of intervals of some description, but I have no idea how to approach the construction of such a thing.
 
Physics news on Phys.org
Hint: fat Cantor set. Look it up.
 
Dick said:
Hint: fat Cantor set. Look it up.


Thank you. I should have thought of that, but only considered the standard Cantor set. Thanks again.
 
GreyZephyr said:
Thank you. I should have thought of that, but only considered the standard Cantor set. Thanks again.

Wow! That was fast. I see that "a word to the wise is sufficient" is sometimes true.
 
Dick said:
Wow! That was fast. I see that "a word to the wise is sufficient" is sometimes true.

I have come across fat cantor sets before and my problem was that I could not think of a closed set whose boundary had positive measure. As soon as you gave the hint the rest followed and I felt like a fool. Oh well such is the learning process. Thanks again for the help, I had been stuck on that for a couple of days.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top