What is binding energy can anyone please explain thank you

jafer
I need to know what is binding energy and how is it equal to the outcome in energy
 
Physics news on Phys.org
In my physics book it says that as the element increase in mass it has more binding energy , but then like heavier elements have lower binding energy like uranium ?
 
I'm thinking that you might be confusing total binding energy and https://courses.engr.illinois.edu/npre201/coursematerial/nuclear_physics/lecture20figures/fig42.jpg.

There is a certain binding energy that keeps a nucleus together and that does generally increase with number of nucleons (although there are exceptions and more complicated features to take into account.

However /how much/ binding energy the nucleus has when you add a nucleon will depend on what you start with. Indeed really heavy nuclei start to get /too/ heavy and adding nucleons to e.g. U235 will not increase the total binding energy as much as e.g. Ne20.

This is reflected in what I called the binding energy per nucleon. This is an average of some sort and you take the total binding energy of the nucleus and divide it by the number of nucleons in the nucleus.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top