What is meant by the input impedance of a voltage source?

AI Thread Summary
The input impedance of a voltage source refers to the impedance perceived by the source rather than an inherent property of the source itself. In circuit design, especially involving operational amplifiers, it's crucial to ensure that the input impedance of voltage sources is at least 100kΩ to prevent loading effects. The discussion highlights confusion around the term "input impedance" as it relates to voltage sources, which do not have traditional inputs. The circuit design problem requires integrating one voltage source while considering the impedance requirements. Understanding that the input impedance is influenced by the load helps clarify the design constraints.
Zarquon
Messages
20
Reaction score
0
I am familiar with the concept of the internal resistance of a voltage source, but what is meant by the input impedance?
 
Physics news on Phys.org
Simon Bridge said:
Have you tried looking up the term?
Can you describe where the regular definitions online lose you?

http://en.wikipedia.org/wiki/Input_impedance

OK, maybe I get it now.. The input impedance of a voltage source is the impedance 'seen' by that source? So it's not a property of the source itself?

In that case I am still confused about this problem I'm supposed to solve (this should maybe go in the homework section, though):

"A circuit has input voltage V1 and V2. Design the circuit so that the output voltage is V0 = 10∫V1dt -5V2.
The input impedance of both voltage sources should be ≥ 100kΩ. Assume ideal op amp."

So if my understanding is correct, then I'm not sure what is being asked for here?
 
A voltage source does not have an "input impedance", since it does not have "inputs".
I think I've seen the term used in the context of a voltage source before but am havig trouble finding an example besides yours.

A circuit has input voltage V1 and V2. Design the circuit so that the output voltage is V0 = 10∫V1dt -5V2.
The input impedance of both voltage sources should be ≥ 100kΩ. Assume ideal op amp.
... you appear to be asked to design a circuit using an op-amp - the circuit in question has two voltage sources in it - which should have some information about frequency and phase as well and amplitude (voltage) if only implied (i.e. perhaps they are variable DC sources?)

When you draw your circuit diagram, the voltage sources should probably be drawn as ideal sources in series with an ideal impedance. Consider: why do the impedances need to be ≥ 100kΩ? What is special about that? How does it impact on the design of the circuit?

Have you had some lessons about op-amp circuits?
Notice that the op-amp has to integrate the first source - do you know how to use the op-amp as an integrator?
 
Last edited:
I agree for the most part. I think the problem is probably referring to the input impedances as seen by the voltage sources. Think of the voltage sources as signal sources that would be loaded down by anything less that 100K ohms. They should probably still be modeled simply as ideal voltage sources.
 
OK, thanks, I get it now. What threw me off whas the fact that I can't decide what the input impedances are, since these will depend on the load; but of course I can make sure that they are greater than 100 kΩ regardless of load.
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top