What is Rf for Op-Amp Circuit w/ Vout=2V & Is=10mA?

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Discussion Overview

The discussion revolves around determining the feedback resistor value (Rf) for an operational amplifier (op-amp) circuit given specific output voltage (Vout = 2V) and input current (Is = 10 mA) conditions. Participants explore the implications of these values on the circuit's behavior, particularly in the context of feedback and linear operation.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant proposes using Kirchhoff's Current Law (KCL) to analyze the circuit, but expresses uncertainty about the approach.
  • Another participant questions the feasibility of achieving Vout = 2V under the given conditions, suggesting that the potential at the op-amp's non-inverting input would be negative, which could lead to a lower output voltage.
  • A suggestion is made that there may be a typo in the problem statement, proposing that the output voltage should be –12V instead of 2V.
  • Further clarification is sought regarding whether the output voltage should indeed be –2V or if the input current should be –10mA.
  • Concerns are raised about the implications of having a negative resistance in the circuit, with one participant expressing confusion over the concept.
  • Another participant reiterates that no combination of the given positive or negative values for Is and Vout seems feasible, indicating a potential contradiction in the problem setup.
  • Discussion continues on the implications of Is being negative, with participants noting that for the amplifier to operate in linear mode, certain voltage conditions must be met, which appear to be violated under the current assumptions.
  • It is noted that in non-inverting mode, the gain cannot be less than 1 unless there is an active feedback mechanism involving another op-amp.

Areas of Agreement / Disagreement

Participants express disagreement regarding the feasibility of the specified output voltage and input current values, with multiple competing views on the implications of these values for the circuit's operation. The discussion remains unresolved, with no consensus reached on the correct interpretation of the problem.

Contextual Notes

Limitations include potential typos in the problem statement, unclear definitions of resistance values, and unresolved mathematical relationships between the circuit parameters.

Metamorphose
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What is Rf --> Op_Amp

1. Consider the amplifier circuit shown. What value of Rf will yield vout = 2V when Is = 10 mA and Ry = 2Rx = 500Ω



2. The way I did this was by employing KCL: (Is that applicable?)



The Attempt at a Solution



Rx(Is) + Rf(Is) = Vout

I'm actually not quite sure how to do this one. It's left me in a bit of a pickle.
 

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Metamorphose said:
1. Consider the amplifier circuit shown. What value of Rf will yield vout = 2V when Is = 10 mA and Ry = 2Rx = 500Ω

I don't see how it's possible. The potential at the op-amp + input will be negative, and feedback should drive the - input to the same value. Thus Vout will be less than that (so long as only positive resistance values are permitted).
 


Perhaps someone has introduced a typo—and that output of 2V should actually be shown as –12V? :smile:
 


As gneil said...

Should that be Vout = -2V or Is = -10mA ?
 


R_y is obviously a negative dc resistance! :bugeye: :eek: :frown:
 


CWatters said:
As gneil said...

Should that be Vout = -2V or Is = -10mA ?

No combination of + or - 10mA and + or - 2V is possible.
 


Humm, you're right.

If Is were -10mA then V+=+5v. For the amp to be in a linear mode V- ≈ V+. However V- can't be +5V if Vo is only 2V.

If Is were -10mA and Vo was -2V you have same problem. V- can't be +5V if Vo=-2V.
 


CWatters said:
Humm, you're right.

If Is were -10mA then V+=+5v. For the amp to be in a linear mode V- ≈ V+. However V- can't be +5V if Vo is only 2V.

If Is were -10mA and Vo was -2V you have same problem. V- can't be +5V if Vo=-2V.

Yup. Point is, in the noninverting mode, the gain can't be less than 1.

Unless you have active feedback (a second op amp configuration feeding the output of the first op amp back to its input.)
 

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