What Is the Acceleration of Masses on a Frictionless Tabletop with Hanging Mass?

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Homework Help Overview

The problem involves two masses, m1 and m2, positioned on a frictionless tabletop, with a third mass, m3, hanging from m1. The coefficients of static and kinetic friction between m1 and m2 are provided, and the original poster seeks to determine the acceleration of both m1 and m2.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the acceleration of m1 and questions how to find the acceleration of m2, considering the role of kinetic friction and Newton's third law.
  • Some participants inquire about the connection between m1 and m2, clarifying that m1 rests on m2 rather than being connected by a string.
  • One participant suggests finding the friction acting on m1 due to m2, noting that this friction will also affect m2's acceleration.

Discussion Status

The discussion is ongoing, with participants exploring the relationships between the masses and the effects of friction. There is no explicit consensus yet, but some guidance regarding the frictional forces has been offered.

Contextual Notes

The original poster has not provided complete information regarding the setup, particularly the nature of the connection between the masses, which has led to clarifications in the discussion.

Marioqwe
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Homework Statement


Two masses, m1 = 3.50kg and m2 = 5.00 kg, are on a frictionless tabletop and mass m3 = 7.60kg is hanging from m1. THE COEFFICIENT OF STATIC AND KINETIC FRICTION BETWEEN m1 AND m2 are 0.60 and 0.50 respectively.

a) What are the acceleration of m1 and m2?

Homework Equations



Equation for kinetic and static friction and Newton's second law.

The Attempt at a Solution



I found the acceleration for m1 to be 5.2 m/s^2 by doing

a = ((m3)g - Fk) / (m1 + m3)

Now, I don't know what to do in order to find the acceleration of m2.
Do I have to consider the kinetic friction between m2 and m1 and Newton's third law meaning that m1 exerts a force equal to Fk (force due to kinetic friction) on m2?
 
Last edited:
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are m1 and m2 connected by string or what?
 
cupid.callin said:
are m1 and m2 connected by string or what?

No no. m1 is resting on top of m2. And m2 is on top of a frictionless table. I forgot to add the part in capital letters to the problem.
 
you can find the friction acting on m1 due to m2
same will act on m2 and cause acceleration in it
 

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