What is the antiderivative of x^2 + (5/x^5) +cos9x - e^-7x?

  • Thread starter Thread starter sntawkin
  • Start date Start date
  • Tags Tags
    Antiderivative
sntawkin
Messages
3
Reaction score
0
What is the antiderivative of x^2 + (5/x^5) +cos9x - e^-7x? I'm so lost...

and also (2x + 5sqrtx)/ x^2
 
Physics news on Phys.org
An anti-derivative of a sum is a sum of anti-derivatives.
 
sntawkin said:
What is the antiderivative of x^2 + (5/x^5) +cos9x - e^-7x? I'm so lost...

and also (2x + 5sqrtx)/ x^2

Well, do you know basic integration rules for powers, exponential, and trigonometric functions?
 
Do it one step at a time (that's what the others are saying). What is the anti-derivative of x2? What is the anti-derivative of 5x-5? What is the anti-derivative of cos(9x)? What is the anti-derivative of e-7x? If you don't know those, you should go back and review your basic formulas.

As for \frac{2x+ 5\sqrt{x}}{x^2}, that's really the same as
\frac{2x}{x^2}+ \frac{5x^{\frac{1}{2}}}{x^2}= 2x^{-1}+ 5x^{-\frac{3}{2}.
The anti-derivatives of those should be easy- use the first anti-derivative formula you learned!
 

Similar threads

Replies
20
Views
4K
Replies
7
Views
2K
Replies
1
Views
1K
Replies
8
Views
2K
Replies
3
Views
1K
Replies
6
Views
3K
Replies
6
Views
2K
Back
Top