What is the area bounded by Y=X^1/2, the x-axis, and 2X+3Y=6?

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To find the area bounded by the curve Y=X^1/2, the x-axis, and the line 2X+3Y=6, first determine the intersection points of the curve and the line to establish limits of integration. The area can be calculated by integrating the difference between the two functions. Some participants suggest considering the integration with respect to y for simplicity. It is noted that this problem resembles a typical homework question, implying that the intersection points may yield simpler values. The discussion emphasizes the importance of correctly identifying the limits and the method of integration for accurate results.
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hello everybody...please could you help me find the solution for this problem??

find the area bounded by the curve Y=X^1/2, the x-axis, and the line 2X+3Y=6.
 
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Find the intersection point of the two lines to get an idea of your limits of integration. After that you'll want to integrate the difference of the two expressions to find the area between them.
 
1. whozum's suggestion

2. Are you sure you copied this correctly? This looks like a homework problem (and so, really should be in the homework section!) and my experience is that, in homework problems, the point of intersection works out more simply than this does.

3. You may find it easier to think of the "height" of the figure as running in the x-direction and integrating with respect to y.
 
thank u

thanks for your help...
 
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