What is the average velocity of the object as it falls to the ground?

AI Thread Summary
An object dropped from a height of 25 meters experiences average velocity during its fall. The calculations show that the time of flight is approximately 2.3 seconds, leading to an average velocity of -10.8 m/s. However, the book states the average velocity as -11.1 m/s, prompting confusion about the correct approach. To resolve this, the kinematic equation relating initial and final velocity to acceleration and time should be used, specifically a = (vf - vi)/t. Understanding that the acceleration due to gravity is -9.8 m/s² is crucial for accurately determining the final velocity just before impact.
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Homework Statement


An object is dropped from a height of 25m above the ground. What is the average velocity of the object as it falls to the ground?


Homework Equations


d=vit+1/2at^2


The Attempt at a Solution


d=-25
a=-9.8
vi=0

-25=-4.9t^2
t=2.3s
vavg=displacement/time
-25/2.3=-10.8m/s
the answer in book says a=-11.1m/s i don't understand, please help?
 
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Use the 2.3 s time of flight to find the velocity just before the object hits the ground. Half of that (because the starting velocity is zero) is the average velocity.
 
I still don't understand, how does that get plugged into the formula? What formula do I use?
Thank you
 
Use the kinematic equation that gives you the velocity of an object at any time t.
 
v=d/t right?
 
Nope. That equation is valid only when the acceleration is zero. Here the acceleration is g down. What equation do you know that relates the initial and final velocity to acceleration and time?
 
a=vf-vi/t right?
 
That's the one. You know everything except vf.
 
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