What Is the Ball's Average Speed During the First 2.7 Seconds?

AI Thread Summary
The discussion revolves around calculating the average speed and velocity of a ball based on its velocity-time graph. The initial calculations for average velocity and speed during the first 2.7 seconds were both determined to be 2.3 m/s. Participants clarified that average speed is always positive, while average velocity can be negative, depending on displacement. For the modified scenarios where the graph segment changes to -3.0 after 2.0 seconds, the average velocity and speed were recalculated, with guidance provided on the correct formulas to use. The conversation emphasizes the importance of careful calculations and understanding the definitions of speed and velocity.
oldspice1212
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Hey guys so I'm stuck and only have a couple tries left meaning I've lost quite some marks on this question already and I can't risk anymore so the question is...

A ball moves in a straight line (the x-axis). The graph in the figure (Figure 1) shows this ball's velocity as a function of time.
http://tinyurl.com/8fkkvrs (graph)

first question was: A) What are the ball's average velocity during the first 2.7 ?

I got 2.3 m/s for this

B) What are the ball's average speed during the first 2.7 ?

2.3 m/s as well but the next two I don't understand what I have to do...


C) Suppose that the ball moved in such a way that the graph segment after 2.0 was -3.0 instead of +3.0 . Find the ball's and average velocity during the first 2.7 in this case.

D) Suppose that the ball moved in such a way that the graph segment after 2.0 was -3.0 instead of +3.0 . Find the ball's average speed during the first 2.7 in this case.
 
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hi oldspice1212! :smile:

speed is always positive (or zero): it's defined that way

in a car, speed is what it says on the speedometer

average speed is average reading of the speedometer​

velocity can be negative (in 2D or 3D, of course, it can be in any direction)

average velocity is total displacement over total time​

show us your next tries at C) and D) before you submit them! :smile:
 
For C I think it's (2+2-2.7)/3 to get the avg velocity which equals 0.43 but I got that wrong I'm not sure what i did wrong there.
 
oldspice1212 said:
For C I think it's (2+2-2.7)/3 to get the avg velocity …

it's not 2.7, and it's not 3 :redface:

are you trying to do too much in your head (or misreading your own handwriting?)
 
Err (2*2-3*0.7)/2.7?
 
oldspice1212 said:
Err (2*2-3*0.7)/2.7?

yup! :smile:
 
Sweet and for D) would it be (2*2+3*0.7)/2.7 = 2.259..2.3
 
yes :smile:
 
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