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What is the capacitance of each capacitor?

  • Thread starter complexc25
  • Start date
12
0
Two capacitors when connected in parallel give an equivalent capacitance of 9.00 pF and an equivalent capacitance of 1.55 pF when connected in series. What is the capacitance of each capacitor?

in parallel:
C1 + C2 = 9.00 pF

in series:
(1/C1) + (1/C2) = (1/1.55pF)

My attempt:
(C1 + C2)/(C1*C2) = 1/1.55

(C1*C2)/(C1+C2) = 1.55

(C1*C2)/9 = 1.55

C2 = (9*1.55)/C1

From here i don't know what to do...
 
Last edited:

Answers and Replies

458
0
You have two equations and two unknowns. Solve for one in terms of another and plug it into a 2nd equation.
 
587
0
Just put C1 = 9 - C2 from the first equation, into the second equation and solve the resulting quadratic equation.
 
12
0
thanx guys :)
 

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