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Two capacitors when connected in parallel give an equivalent capacitance of 9.00 pF and an equivalent capacitance of 1.55 pF when connected in series. What is the capacitance of each capacitor?

in parallel:

C1 + C2 = 9.00 pF

in series:

(1/C1) + (1/C2) = (1/1.55pF)

My attempt:

(C1 + C2)/(C1*C2) = 1/1.55

(C1*C2)/(C1+C2) = 1.55

(C1*C2)/9 = 1.55

C2 = (9*1.55)/C1

From here i don't know what to do...

in parallel:

C1 + C2 = 9.00 pF

in series:

(1/C1) + (1/C2) = (1/1.55pF)

My attempt:

(C1 + C2)/(C1*C2) = 1/1.55

(C1*C2)/(C1+C2) = 1.55

(C1*C2)/9 = 1.55

C2 = (9*1.55)/C1

From here i don't know what to do...

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