What is the Capacitance of the Unknown Capacitor in the Circuit?

AI Thread Summary
The problem involves a series circuit with an 11.6k ohm resistor and an unknown capacitor connected to a 180 V battery, where the voltage across the capacitor after one second is 16.8 V. To find the capacitance, the differential equation for the charging capacitor can be derived using Kirchhoff's Voltage Law. The solution to this equation is in the form V_c(t) = V_o(1 - e^{-t/τ}), where τ is the time constant (RC). By substituting the known voltage values into this equation, the capacitance can be calculated. This approach provides a clear method to determine the unknown capacitance based on the circuit's parameters.
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Homework Statement



a series combinations is 11.6k ohms resistor and an unknown capacitor is connected to the a 180 V battery. One second after the circuit is completed, the voltage across the capacitor is 16.8v. determine the capacitance of the capacitor?

Homework Equations



V=18
C?
1 sec later
V=16.8v

The Attempt at a Solution


c= q/v
i=v/r
 
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Derive the differential equation for the current/voltage across the capacitor when it's charging, using Kirchoff's Voltage Law, and solve.

Or if you're allowed to, just look up the solution of this equation, which should be in the form V_c (t) = V_o (1 - e^{-t/\tau}) where \tau is the time constant RC. You can then plug in your known values of V_c to solve for the capacitance.
 
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