What is the Centripetal Acceleration of a Car on a Circular Curve?

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The centripetal acceleration of a car negotiating a flat circular curve with a radius of 50 m at a speed of 20 m/s is calculated using the formula A_c = V^2/R. Substituting the values, the calculation yields 8 m/s². The maximum centripetal force provided by static friction is noted but does not affect the calculation of acceleration directly. Some participants express confusion over the relevance of additional details provided in the problem. Ultimately, the focus remains on the straightforward application of the centripetal acceleration formula.
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Homework Statement



A car is negotiating a flat circular curve of radius 50 m with a speed of 20 m/s. The maximum centripetal force (provided by static friction) is 1.2 × 104 N. What is the centripetal acceleration of the car?


Homework Equations



MAc = MV^2/R

The Attempt at a Solution



20^2 / 50 = 8 m/s^2 ?
 
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robvba said:

Homework Statement



A car is negotiating a flat circular curve of radius 50 m with a speed of 20 m/s. The maximum centripetal force (provided by static friction) is 1.2 × 104 N. What is the centripetal acceleration of the car?


Homework Equations



MAc = MV^2/R

The Attempt at a Solution



20^2 / 50 = 8 m/s^2 ?

Not sure, but I think you're right. I have no idea what the second sentence actually means, but it might just be a red herring. Cent acc is just velocity squared over radius, and they gave you that in the first sentence.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
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