- #1
NeomiXD
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Fred (60 kg) is rollerblading at a velocity of 25 km/h [E] when he sees a broken glass bottle on the path ahead. He brakes and is slowed to a velocity of 8 km/h [E] in 4.2 s. What is the coefficient of friction between Fred's rollerblades and the ground? (Hint: Find FN and Ff first.)
Given:
m = 60 kg
v1 = 25km/h = 6.94m/s [E]
v2 = 8km/h = 2.20m/s [E]
Δt = 4.2s
g = 9.8 N/kg
Required:
?
Solution:
Fg = mg
Fg = (60kg) (9.8 N/kg)
Fg = 588 N
FN = Fg
FN = 588 N
Ff ≤ µs FN
Ff ≤ µs (588 N)
??
I don't know what to do after.
µs is not given, so how do you solve this question?
Given:
m = 60 kg
v1 = 25km/h = 6.94m/s [E]
v2 = 8km/h = 2.20m/s [E]
Δt = 4.2s
g = 9.8 N/kg
Required:
?
Solution:
Fg = mg
Fg = (60kg) (9.8 N/kg)
Fg = 588 N
FN = Fg
FN = 588 N
Ff ≤ µs FN
Ff ≤ µs (588 N)
??
I don't know what to do after.
µs is not given, so how do you solve this question?