What is the Coefficient of Kinetic Friction and Acceleration in a Pulley System?

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Homework Help Overview

The discussion revolves around a pulley system involving two blocks, Block A on a table and Block B hanging down. The original poster is attempting to calculate the coefficient of kinetic friction between Block A and the tabletop, as well as the acceleration of Block B when it is set into motion. The scenario includes considerations of forces acting on both blocks and the implications of Block B descending at a constant speed.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are discussing the relationship between the forces acting on the blocks, particularly the frictional force and its dependence on the weights of the blocks. Questions are raised about the correct expression for the coefficient of kinetic friction and the implications of Block B's constant speed on the forces involved.

Discussion Status

There is an ongoing exploration of the expressions for the forces involved, particularly the frictional force. Some participants are questioning the assumptions made regarding the motion of Block A and the significance of Block B's constant speed. Guidance has been offered in the form of prompting participants to clarify their understanding of the forces at play.

Contextual Notes

Participants are navigating the complexities of the problem, including the need to express the frictional force in terms of known variables and the implications of the system being in equilibrium at certain points. There is a noted uncertainty regarding the values of forces and their relationships.

Soaring Crane
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Block A has weight w_A and block B has weight w_B. Block A is positioned on the horizontal surface of a table. Block A is connected to a cord passing over an easily turned pulley that has Block B hanging down from the pulley. Once Block B is now set into downward motion, it descends at a constant speed.

a. Calculate the coefficient of kinetic friction between Block A and the tabletop.

I drew Block A's force diagram. For this part, I am assuming Block A is not in motion as yet; it is just sitting on the tabletop. (Is this correct?)

Well, F_fr = mu_K * F_N and the normal force = w_A.

F_fr = mu_k*w_A

mu_k = F_fr/w_A

But I think this is somewhat incorrect. Musn't I express mu_k with the known variables give. What is the Value for F_fr? :confused:

b. A cat, also of weight w_A, falls asleep on top of block A. If Block B is now set into downward motion, what is its acceleration (magnitude and direction)? Express a in w_A, w_B, and g.

Well, I am unsure of the F_fr expression. This is what I did for this part.

For Block A, the expression is now F_T - F_fr = [(2*w_A)/g]*a
For Block B, ---------------------w_B - F_T = (w_B/g)*a

Adding these two expressions, I get

w_B - F_fr = [(2*w_A)/g]*a + (w_B/g)*a
w_B - F_fr = a[(2*w_A + w_B)/g]

a = [w_B - F_fr]/[(2*w_A + w_B)/g]
a = g*[(w_B-F_fr)/(2*w_A + w_B)]

But I don't know what to put for F_fr as noted in the first part.

Are my reasonings and math that I did do correct?

Thanks.
 
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Block A has weight w_A and block B has weight w_B. Block A is positioned on the horizontal surface of a table. Block A is connected to a cord passing over an easily turned pulley that has Block B hanging down from the pulley. Once Block B is now set into downward motion, it descends at a constant speed.

a. Calculate the coefficient of kinetic friction between Block A and the tabletop.

I drew Block A's force diagram. For this part, I am assuming Block A is not in motion as yet; it is just sitting on the tabletop. (Is this correct?)

Well, F_fr = mu_K * F_N and the normal force = w_A.

F_fr = mu_k*w_A

mu_k = F_fr/w_A

But I think this is somewhat incorrect. Musn't I express mu_k with the known variables give. What is the Value for F_fr?
One may assume block A has zero velocity.

To find F_fr, what is F_fr opposing? What is the significance of Block B descending at constant speed?
 
F_fr = w_B, but when I plug this value into the expression for a that I found, acceleration would be 0. According to Newton's First Law, a body that has constant velocity and, therefore, 0 acceleration is acted on by no net forces. Where do I go from here?
 
Soaring -- didn't your last post just answer your own question? In your first post, you wanted to know what F_fr was. So, what is it?
 

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