What Is the Common Velocity After Collision on a Frictionless Incline?

AI Thread Summary
The discussion revolves around a physics problem involving two blocks on a frictionless incline and their collision with a spring. The key equation for understanding the system is the conservation of mechanical energy, which states that the initial kinetic and potential energy equals the final kinetic and potential energy. During the collision, the kinetic energy of the blocks is not conserved as they stick together and compress the spring. After the collision, the blocks come to rest, resulting in zero kinetic energy at that final state. Understanding these principles is crucial for solving the problem and determining the common velocity after the collision.
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Homework Statement


A block is on a frictionless incline. A block at the bottom of the incline is resting up the incline against a spring. The first block is released. The blocks stick and compress the spring. What is the common velocity immediately after collision?

Homework Equations



Kinetic energy of the two blocks + potential energy of blocks = potential energy of spring

The Attempt at a Solution



I am not concerned with solving this equation for the velocity. I am just concerned with understanding how to get to this equation. My exam useful equations study sheet shows that kinetic initial+ potential initial = kinetic final + potential final.
 
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Is the kinetic final canceled out because velocity would be zero at the final state?
 
mrshappy0 said:
I am just concerned with understanding how to get to this equation. My exam useful equations study sheet shows that kinetic initial+ potential initial = kinetic final + potential final.
That equation applies when mechanical energy is conserved. (Which is not the case during the collision of the two blocks.)

mrshappy0 said:
Is the kinetic final canceled out because velocity would be zero at the final state?
In the final position, the blocks are at rest. So their kinetic energy is zero.
 
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