What is the connection between energy eigenstates and position?

In summary: So, if we square the wave function (take the square of the amplitude), we get a position probability.
  • #1
jeebs
325
4
The first thing I remember hearing about in QM was the time-independent 1-D schrodinger equation, [itex] Hψ = (\frac{-\hbar^2}{2m}\frac{d^2}{dx^2} + V)ψ(x) = Eψ(x) [/itex]. This is an eigenvalue equation, the Hamiltonian operator H operating on the energy eigenstate ψ to produce the product of the energy eigenvalue, E, and ψ.

However, we also come to know this state ψ by another name, the "wavefunction", and we find that if we take |ψ(x)|^2 we find the probability of finding our particle at at position x.

My question is, what is it about the eigenstates of the energy operator in particular that should mean we can find out this information about the likelihood of a particle occupying a certain position x upon measurement? I don't see the connection - especially seeing as we could take a free particle (V=0) so that the energy of the particle has no dependence on position, only momentum?
In other words, why don't we take any other eigenstate for any other observable quantity, square that and use that for our position probability?
 
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  • #2
You can choose to express your wavefunction in any complete basis. The thing that's special about the energy eigenbasis is it gives you an easy way to evolve the states in time. The Born postulate has nothing to do with energy eigenbases.
 
  • #3
the wave function solutions of the Schrodinger equation for any system are solutions in a "state space" within the Hilbert Space. The Hilbert space is a space where the elements of the space are solutions to the wave equation (where the operation is just the inner product). A state of a quantum mechanical system is then a vector in the Hilbert space, and observables (which act as operators in Quantum mechanics) are a type of linear operator. Like any linear operator there exists a matrix representation allowing for our eigen value to be relevant. But the fact that these eigen-values correspond to the systems energy comes solely from the derivation of the Schrodinger equation which uses De Broglie's relations and the least action principle to find a wave form from particle quantisation. The fact energy became the scalar acting as a eigen-value for an eigen-value equation was a beautiful by-product.
The state space is not limited to a position representation. ANY observable my act as the linear operator in our Hilbert space.
 

1. What are energy eigenstates?

Energy eigenstates are specific quantum states that describe the energy levels of a system. In these states, the total energy of the system is well-defined and cannot be changed without external influence.

2. How are energy eigenstates related to position?

The energy eigenstates of a system are directly related to the position of the particles within the system. In fact, the energy eigenstate with the lowest energy level is associated with the most probable position of the particles.

3. What is the significance of energy eigenstates in quantum mechanics?

Energy eigenstates play a crucial role in understanding the behavior of quantum systems. They allow us to calculate the energy levels and probabilities of different states, which can then be used to make predictions about the behavior of the system.

4. How do energy eigenstates affect the uncertainty principle?

The uncertainty principle states that it is impossible to simultaneously know the exact position and momentum of a particle. Energy eigenstates help to reduce this uncertainty by providing a more precise measurement of the position of the particles in a system.

5. Can energy eigenstates change over time?

No, energy eigenstates are stationary states and do not change over time. However, a system can transition from one energy eigenstate to another through a process called quantum tunneling.

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